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Colt1911 [192]
3 years ago
6

The points (3, 2) and ( -2, -3) are solutions to a system of two linear equations. What must be true about the two linear equati

ons?
Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

The two linear equations are the same line

Step-by-step explanation:

two different linear equations can only possibly intersect at one point. once the two lines intersect, they cannot curve back to intersect once again.

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When I divide 58.4 by 9.6, I get the digits 6 0 8 3Explain how you can use estimation to correctly place the decimal point. Be s
Anastaziya [24]

Answer:

See below

Step-by-step explanation:

58.4/9.6 can be rewritten as 58/10=5.8, so the decimal point will go between the first and second digits. Therefore, 58.4/9.6=6.083

6 0
3 years ago
Whats the answer for this
drek231 [11]

Answer:

50/18 or 2.77

Step-by-step explanation:

So first u have to make the 3 1/3 and 1 1/5 into improper fractions.

Then, you can do the keep, change, flip thing and then u get 10/3 x 5/6 to get 50/18

7 0
3 years ago
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insens350 [35]
1x16
2x8
is the answer
3 0
3 years ago
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Lim x--> 0 (e^x(sinx)(tax))/x^2
Tom [10]

Make use of the known limit,

\displaystyle\lim_{x\to0}\frac{\sin x}x=1

We have

\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)

since \tan x=\dfrac{\sin x}{\cos x}, and the limit of a product is the same as the product of limits.

\dfrac{e^x}{\cos x} is continuous at x=0, and \dfrac{e^0}{\cos 0}=1. The remaining limit is also 1, since

\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1

so the overall limit is 1.

4 0
3 years ago
Steven investigates the amount of damage to the head gaskets on the trucks in his fleet and finds that the damage index depends
pshichka [43]

answer- it is D because.2/3 is decrease.

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