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3 years ago

Can someone help me with this? I'm kinda confused.

Mathematics

2 answers:

Arlecino [84]3 years ago

7 0

Answer:

It's C

Step-by-step explanation:

I told u in the comment thing, ad when you go from 1 up, it leads to 9.5

ella [17]3 years ago

5 0

Answer:

C-cashews cost $9.50 pound

Step-by-step explanation:

You might be interested in

Mark earned 108 points for his extra credit project.

Juli2301 [7.4K]

Answer:

120 points

Step-by-step explanation:

Let the total points be x

<u>Mark earned 90% of x which is 108 points:</u>

0.9x = 108
x = 108/0.9
x = 120

Total points were 120

5 0

3 years ago

Find the value of two numbers if their sum is 19 and and their difference is 5

sergij07 [2.7K]

Answer:

7 and 12

Step-by-step explanation:

x - y = 5

y = (5+x)

x+ (5+x) = 19

2x +5 = 19

2x = 14

x = 7

19-7 = 12

12 +7 = 19

12-7 = 5

7 0

3 years ago

Read 2 more answers

Plz help I don’t get this

Law Incorporation [45]

Mary has 48 stickers. The ratio is 4:7

divide 48 with 4

48/4 = 12

Multiply 12 with 7

12 x 7 = 84

Mary buys another 8 stickers: 48 + 8 = 56

56:84 is the new ratio

hope this helps

7 0

3 years ago

In 2010, Fernando paid $1,810 in federal income tax. In 2011, he paid $816. What is the percent of decrease in the amount paid

Mama L [17]

Answer:

45%

Step-by-step explanation:

816 divided by 1,810 is .45

6 0

2 years ago

Is the sum of an irrational number and rational number always irrational?

MissTica

Yes.

It can be proved by contradiction.

Let:
a - a rational number
b - an irrational number
c - the sum of a and b

$a+b=c$

Let assume that c is a rational number. Then a and c can be expressed as fractions with integer numerator and denominator:
$a=\dfrac{d}{e}\\
c=\dfrac{f}{g}\\$ where $d,e,f,g \in \mathbb{Z}$

$\dfrac{d}{e}+b=\dfrac{f}{g}\\
b=\dfrac{f}{g}-\dfrac{d}{e}\\
b=\dfrac{ef}{eg}-\dfrac{dg}{eg}\\
b=\dfrac{ef-dg}{eg}$

Since $d,e,f,g$ are all integers, then the products $ef,dg,eg$ and the difference $ef-dg$ are integers as well. It means that the number $b$ is a rational number, but this on the other hand contradicts the earlier assumption that $b$ is an irrational number. Therefore $c$ must be an irrational number.

8 0

3 years ago