Question

There are 10 kids on the math team. Two kids will be selected from the team to compete in the state competition. How many ways are there to select the 2 competitors?

Answer 1

Answer:

45 ways

Step-by-step explanation:

Total number of kids = 10

We have to select the 2 kids

So the number ways to select two kids $^{10}C_2$

We know that $^{n}C_r=\frac{n!}{r!(n-r)!}$

So $^{10}C_2=\frac{10!}{2!(10-2)!}=\frac{10!}{2!\times 8!}=\frac{10\times 9\times 8!}{2\times 8!}=45$

So there are 45 ways to select 2 competitors