<h2>
Answer:</h2>
Luke does a work of 308Nm
<h2>
Step-by-step explanation:</h2>
If we have a constant force
that acts on a body in the same direction as the displacement
, then the work
is defined as the product of the force magnitude
and the displacement magnitude
. In other words:
, which is valid for a constant force in direction of straight-line displacement.
In this problem:
![F=22N \\ \\ s=14m](https://tex.z-dn.net/?f=F%3D22N%20%5C%5C%20%5C%5C%20s%3D14m)
Therefore:
![W=22\times 14 \\ \\ \boxed{W=308Nm}](https://tex.z-dn.net/?f=W%3D22%5Ctimes%2014%20%5C%5C%20%5C%5C%20%5Cboxed%7BW%3D308Nm%7D)
Yeah around 41%, what u can do to get the answer is just 20 divided by 48
Answer:
Slope= m = Δy/Δx = (y₂-y₁)/(x₂-x₁) = rise / run
Step-by-step explanation:
Hope that helps . Just plug in your values if you are given two points
for example: (3,4) = (x₂,y₂) (1,2) = (x₁,y₁)
Just substitute in the equation above
(4-2)/(3-1) = 2/2 =1
good luck
Answer:
D. r(t) = (10 + 12t, 5 + −34t, 6 + −6t)
Step-by-step explanation:
Hope this helps