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3 years ago

HELP Eliminating the parameter! x = 2t - 3, y = 9 - 4t 3 ≤ t ≤ 5

1 answer:

5 0

$\begin{cases}x=2t-3\\y=9-4t\end{cases}$
$x=2t-3\iff t=\dfrac{x+3}2$
$\implies y=9-4\left(\dfrac{x+3}2\right)=9-2(x+3)$
$\implies y=3-2x$

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