Question

HELP Eliminating the parameter! x = 2t - 3, y = 9 - 4t 3 ≤ t ≤ 5

Answer 1

$\begin{cases}x=2t-3\\y=9-4t\end{cases}$
$x=2t-3\iff t=\dfrac{x+3}2$
$\implies y=9-4\left(\dfrac{x+3}2\right)=9-2(x+3)$
$\implies y=3-2x$