x= morning
y = afternoon
x + y = 10
x=10-y
5x + 6y =57
5(10-y) +6y =57
50-5y +6y =57
y=7
x=10-7 =3
check 3*5 = 15, 7*6 = 42, 42 + 15 = 57
3 morning practices
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
Answer:
1. y = x2+2
2. g = (-3x+1)/x
Step-by-step explanation:
1. No explanation
2.
Let's solve for g.
gx=1−3x
Step 1: Divide both sides by x
gx
/x = −(3x+1
)/x
g = (-3x+1)/x
Hope it helped!
4 = $26
26/4 = $6.50
1 ticket = $6.50
6.5 x 3 =19.50
26+19.50 = 45.50
7 tickets = $45.50
Tyler had 24 pieces of gum he split the pieces among his 3 friends and himself, How many pieces did each one get? Divide 24 by 4 then you get 6. so Tyler and his 3 friends each get 6 pieces of gum.
