Simplify: Cube root of (128a^13b^6)
1 answer:
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Let sin⁻¹(
) = x
Therefore, sin(x) =
x should lie in first quadrant because √3 and 2 both are positive.
Therefore, sin(x) = 60° = π/3
Therefore, sin(x) =
x should lie in first quadrant because √3 and 2 both are positive.
Therefore, sin(x) = 60° = π/3
now, let's recall the rational root test, check your textbook on it.
so p = 18 and q = 1
so all possible roots will come from the factors of ±p/q
now, to make it a bit short, the factors are loosely, ±3, ±2, ±9, ±1, ±6.
recall that, a root will give us a remainder of 0.
let us use +3.
well, that one worked... now, using the rational root test, our p = 6, q = 1.
so the factors from ±p/q are ±3, ±2, ±1
let's use 3 again
and of course, we can factor x²-x-2 to (x-2)(x+1).
(x-3)(x-3)(x-2)(x+1).
