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saveliy_v [14]
3 years ago
11

A sample was taken of dogs at a local dog park on two random days. The counts are displayed in the table below. If there are est

imated to be 50 dogs at the park at any given time, which proportion could be used to find the average number of shepherd mixes at the park at any given time?
Dog Park Sample
Sample 1
Sample 2
Labrador Retriever
4
Labrador Retriever
5
Shepherd Mix
7
Shepherd Mix
9
Chihuahua
3
Chihuahua
5
Poodle
1
Poodle
2
Australian Cattle Dog
2
Australian Cattle Dog
4
StartFraction 8 over 21 EndFraction = StartFraction x over 50 EndFraction
StartFraction 16 over 21 EndFraction = StartFraction x over 50 EndFraction
StartFraction 8 over 50 EndFraction = StartFraction x over 42 EndFraction
StartFraction 7 over 9 EndFraction = StartFraction x over 50 EndFraction
Mathematics
2 answers:
deff fn [24]3 years ago
8 0

Answer:

its a

Step-by-step explanation:

i took the test also the dude aboves was really confusing e d g e n u i t y 2 0 2 0 is a

marusya05 [52]3 years ago
4 0
Sample one and two labrador
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Darina [25.2K]

Step 1: Both sides are divided by 2.

Step 2: 3 is added to both sides.

Step 3: Both sides are divided by 6.

A: x + 3 = 4/3 + 3

B: x+3/6 = (4/3 + 3)/6

C: x+3/12 = (4/3 + 3)/12

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2 years ago
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Leni [432]

Answer:

First paper : third choice

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Step-by-step explanation:

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3 years ago
Which expression is equivalent to
statuscvo [17]

Answer:

\fbox{16(0.5x  - 0.75y + 2)}

Step-by-step explanation:

8x - 12y + 32

Take 4 common first,

4(2x - 3y + 8)

Since we need 16 outside the bracket, multiplying and dividing by 4,

4 \times  \frac{4}{4} (2x - 3y + 8)

16( \frac{2}{4} x -  \frac{3}{4} y +  \frac{8}{4} )

Simplifying all the fractions,

\fbox{16(0.5x  - 0.75y + 2)}

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2 years ago
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Step-by-step explanation:

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