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ohaa [14]
3 years ago
9

Math questions!! you will get brainly!

Mathematics
2 answers:
Firlakuza [10]3 years ago
7 0
I didn't get 4 but I hope this is right

mamaluj [8]3 years ago
4 0
Drag the tiles to the correct boxes to complete the pairs.
Find the distance between each pair of points.
6 units
5 units
2 units
4units
3 units

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Y = 0.95X 7.95<br> Write and solve a linear equation to find how many songs he downloaded
Dmitry [639]
0.95 x 7.95 = 7.5525
5 0
3 years ago
Solve : <br>4² ( 4³ )<br>with work shown ​
stepan [7]

Answer:

1024

Step-by-step explanation:

4²(4³)

4×4(4×4×4)

16(16×4)

16(64)

16×64

=1024

7 0
2 years ago
How to find the average squared distance between the points of the unit disk and the point (1,1)
ddd [48]
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)
=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
=r^2-2r(\cos\theta-\sin\theta)+2

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}
=\dfrac{\frac{5\pi}2}\pi=\dfrac52
5 0
3 years ago
2a^2-5a=3 solve by factoring
Amiraneli [1.4K]

Answer:

a=−1/2, 3

3Step-by-step explanation:

6 0
2 years ago
) [7 − 2x + 5y − (x − y)] − (5x + 3y − 7)​
ale4655 [162]

Answer:

[7-2x+5y-(x-y) -[5x+3y-7]

= 7-2x+5y-x+y-5x-3y+7

=7+7-2x-x-5x+5y+y-3y

=14-8x+3y

=-8x+3y+14

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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