Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
4/5 mile in 1/2 hour.
1/2 * 2 = 1
4/5 * 2 = 8/5
8/5 miles per hour or 1.6 miles per hour
356/8 = 44.5
44.5 miles per hour, miles/hour
Set up the following equations:


110 represents the lengths of the length and width of the triangle, as you'll divide total perimeter of the rectangle, 220, by 2 to find the individual lengths. 20 is the difference between the length and width.
We'll use elimination for this system of equations, as there are opposite coefficients for W in both equations. Combine the two equations:

Divide both sides by 2 to get L by itself:
The length of the rectangle is 65 feet.Plug this value into the second equation:

Add W to both sides:

Subtract 20 from both sides:
The width of the rectangle is 45 feet.