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bogdanovich [222]
3 years ago
12

IF P(A)=1/3, P(B)=2/5, and P(AuB)=3/5, what is P(A^B)?

Mathematics
1 answer:
Bumek [7]3 years ago
3 0

The probability of the union of two events is the sum of their probability, minus the probability of their interserction:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

If we plug the known values into this formula, we have

\dfrac{3}{5} = \dfrac{1}{3} + \dfrac{2}{5} - P(A\cap B)

From which we can deduce

P(A\cap B) = \dfrac{1}{3} + \dfrac{2}{5} - \dfrac{3}{5} = \dfrac{2}{15}

So, the probability of A \setminus B is a bit less than P(A), we have to take away all events that belong to B as well:

P(A \setminus B) = P(A) - P(A\cap B) = \dfrac{1}{3} - \dfrac{2}{15} = \dfrac{1}{5}

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