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2 years ago

9

Ui5 -4 Solve each equation. 1) 2a - 8a = 12 - 8a

1 answer:

vredina [299]2 years ago

3 0

Answer:

Sorry, I forgot what the a means

Step-by-step explanation:

is it multiplcation , division, subtraction, or addition?

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Write an equation in slope intercept form for the trend line shown below.

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3 years ago

Sean's house is currently worth $188,900. According to a realtor, house prices in Sean's neighborhood will increase by 4.8% ever

mrs_skeptik [129]

Answer

Given

Sean's house is currently worth $188,900.

According to a realtor, house prices in Sean's neighborhood will increase by 4.8% every year.

To prove

Formula

$Compound\quaterly\ interest = Principle (1 + \frac{r}{4})^{4t}$

Where r is the rate in the decimal form.

As given

$Take\ Principle\ = P_{0}$

$Rate = \frac{4.8}{100}$

= 0.048

Put in the formula

$Compound\quaterly\ interest = P_{0}(1 + \frac{0.048}{4})^{4t}$

$Compound\quaterly\ interest = P_{0} (1 + \frac{0.048}{4})^{4t}$

$Compound\quaterly\ interest = P_{0} (1 + 0.012)^{4t}$ $Compound\quaterly\ interest = P_{0} (1.012)^{4t}$

Now also calculated monthly.

Formula

$Compound\ monthly = Principle (1 + \frac{r}{12})^{12t}$

As given

$Take\ Principle\ = P_{0}$

$Rate = \frac{4.8}{100}$

= 0.048

Put in the formula

$Compound\ monthly = P_{0} (1 + \frac{0.048}{12})^{12t}$

$Compound\ monthly = P_{0} (1 + 0.004)^{12t}$

$Compound\ monthly = P_{0} (1.004)^{12t}$

As the approximation quarterly growth rate of the value of sean's house is near the Compounded quarterly interest .

Thus Option (A) is correct.

i.e

The expression $(1.0118)^{4t}$ reveals the approximate quarterly growth rate of the value of Sean's house.

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