Answer:
14.4841
Step-by-step explanation:
The answer is 6.
5(4) -2(7)
20-14=6
Step-by-step answer:
The general form of an equation centered at O(0,0) is given by
x^2+y^2=r^2
where r is the radius, (x,y) is any point on the circumference.
If B(4,5) lies on the circumference, then we can find the radius of the circle by substitution:
4^2+5^2=r^2
=>
r^2 = 16+26 =41
Hence the equation of a circle centred at O(0,0) and B(4,5) on its circumference is
x^2 + y^2 = 41
-40 +2n= 4n -8(n+8)
-40 +2n= 4n -8n -64
-40 + 2n = -4n -64
2n = -4n -64 +40
2n=-4n-24
2n+4n=-24
8n=-24
N= -3
Answer is n equals -3
The -3 would be where your line crosses the y-axis, so you would plot your point at -3. your slope will always be counted as rise/run, basically meaning you would count along the y-axis a certain amount of times, in this case -1, and along the x-axis a certain amount of times, here would be three. your next plot point would be (3,-4) and so on. hope this helped!
