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Advocard [28]
3 years ago
6

If $4000 is borrowed at a rate of 16% interest

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

(a) $7492

(b) $10,253

(c) $14,032

Step-by-step explanation:

As we know, the final Amount can be calculated with the formula for compound interest,

A = P(1 + \frac{r}{n} )^{nt}

where,

A = Final Amount due

P = Initial principal amount borrowed

r = rate of interest in decimal

n = number of times applied per time period

t = total time period

Now, according to the given data,

(a) in 4 years ;-

⇒ A = 4000(1 + \frac{0.16}{4} )^{4(4)}

⇒ A = 7492

(b) in 6 years ;-

⇒ A = 4000(1 + \frac{0.16}{4} )^{4(6)}

⇒ A = 10,253

(c) in 8 years ;-

⇒ A = 4000(1 + \frac{0.16}{4} )^{4(8)}

⇒ A = 14,032

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Answer:

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Step-by-step explanation:

We know distance formula,

D = RT

Where

D is distance

R is rate

T is time

If we let speed of boat (assume) to be "x" and speed of current to be "c"

Then downstream rate is (with current) = x + c

Upstream rate is (against current) = x - c

40 mins to go 20 miles downstream, that means:

D = RT

20 = (x + c)(40)

and

60 minutes to go upstream, 20 miles, that means:

D = RT

20 = (x - c)(60)

Simplifying first equation:

40x + 40c = 20

Simplifying second equation:

60x - 60c = 20

Multiplying first equation by 60, we get:

60 * [40x + 40c = 20] = 2400x + 2400c = 1200

Multiplying second equation by 40, we get:

40 * [60x - 60c = 20] = 2400x - 2400c = 800

Now we add up both these equations:

2400x + 2400c = 1200

2400x - 2400c = 800

----------------------------------

4800x = 2000

x = 2000/4800 = 5/12

We need speed of current, that is "c", so we plug in the value of x into first equation and solve for c:

40x + 40c = 20\\40(\frac{5}{12}) + 40c = 20\\\frac{50}{3}+40c=20\\40c=20-\frac{50}{3}\\40c=\frac{10}{3}\\c=\frac{1}{12}

Speed of Current = 1/12 miles per minute

Since there is 60 minutes in an hours, that would be:

(1/12) * 60 = 5 miles per hour

Speed of Current = 5 miles per hour

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