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Advocard [28]
3 years ago
6

If $4000 is borrowed at a rate of 16% interest

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

(a) $7492

(b) $10,253

(c) $14,032

Step-by-step explanation:

As we know, the final Amount can be calculated with the formula for compound interest,

A = P(1 + \frac{r}{n} )^{nt}

where,

A = Final Amount due

P = Initial principal amount borrowed

r = rate of interest in decimal

n = number of times applied per time period

t = total time period

Now, according to the given data,

(a) in 4 years ;-

⇒ A = 4000(1 + \frac{0.16}{4} )^{4(4)}

⇒ A = 7492

(b) in 6 years ;-

⇒ A = 4000(1 + \frac{0.16}{4} )^{4(6)}

⇒ A = 10,253

(c) in 8 years ;-

⇒ A = 4000(1 + \frac{0.16}{4} )^{4(8)}

⇒ A = 14,032

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Answer:

Each friend donates $10.

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For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
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Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

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Step-by-step explanation:

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A) (3x + 9i)(x + 3i)
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B) (3x - 9i)(x + 3i)
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C) (3x - 6i)(x + 21i)
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=  - 126i^2 + 57ix + 3x^2






D) (3x - 9i)(x - 3i)
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= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
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= 9ix + 3x^2 + 27i - 9x









Hope that helps!!!

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