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FromTheMoon [43]
3 years ago
10

Two urns both contain green balls and red balls. Urn I contains 4 green balls and 8 red balls and Urn II contains 2 green balls

and 5 red balls. A ball is drawn from each urn. What is the probability that both balls are red? a. 10/21 b. 2/21 c. 5/21 d. 5/84 Please select the best answer from the choices provided A B C D
Mathematics
1 answer:
wolverine [178]3 years ago
5 0

Answer: 10/21

Step-by-step explanation:

From the question, we are told that two urns both contain green balls and red balls. Urn I contains 4 green balls and 8 red balls and Urn II contains 2 green balls and 5 red balls.

Urn 1 contains 4 green balls and 8 red balls. This means that the probability of drawing a red ball in urn 1 will be 8/12 = 2/3.

Urn II contains 2 green balls and 5 red balls. This means that the probability of drawing a red ball in urn 2 will be 5/7

Since we've the probability of drawing a red ball from both urns, we then multiply them together. This will be:

= 2/3 × 5/7

= 10/21

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Answer:

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Step-by-step explanation :

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IRINA_888 [86]

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olga55 [171]
Is this the full question
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? ÷ 100,000 = 4.3976<br> ? ÷ 100,000 = 439.76<br> ? ÷ 100,000 = 4,397.6<br> ? ÷ 100,000 = 439,760
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Answer:

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Step-by-step explanation:

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