All categories

3 years ago

I need to know the answer.

Mathematics

1 answer:

katrin [286]3 years ago

5 0

Well, apologies if this is wrong but in my opinion, I think it's that The angles do not change. This is because the angles are alright staying in the same place. I don't understand much about angles but it makes the most sense to me.

You might be interested in

Ab and bc form a right angle at point B. if a= (-3,-1) and B= (4,4) what is the equation of BC?

Vesnalui [34]

Answer:

Option C $-7x-5y=-48$

Step-by-step explanation:

step 1

Find the slope of AB

we have

A(-3,-1) and B(4,4)

The slope m is equal to

$m=(4+1)/(4+3)$

$m=5/7$

step 2

Find the slope of BC

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

$m1*m2=-1$

we have

$m1=5/7$

substitute

$5/7*m2=-1$

$m2=-7/5$

step 3

Find the equation of the line into slope point form

$y-y1=m(x-x1)$

we have

$m=-7/5$

$B(4,4)$

substitute

$y-4=-(7/5)(x-4)$

Multiply by 5 both sides

$5y-20=-7x+28$

$7x+5y=28+20$

$7x+5y=48$

Multiply by -1 both sides

$-7x-5y=-48$

3 0

3 years ago

What is the area of the rectangular piece of wood?

Mama L [17]

Answer:

2x^2 + 7x + 3 is the area of the rectangular piece of wood.

Step-by-step explanation:

Here,

Length ( l ) = x + 3

Breadth ( b ) = 2x + 1

Formula : -

Ar ( rectangle ) = lb

= ( x + 3 ) ( 2x + 1 )

= x ( 2x + 1 ) + 3 ( 2x + 1 )

= 2x^2 + x + 6x + 3

= 2x^2 + 7x + 3

6 0

3 years ago

25+1/4? ( explain the steps)

Lena [83]

The answer is 25 1/4. to solve this you can do 4x25 plus 1 divided by 4. 4x25 is 100 plus 1 equals 101

5 0

3 years ago

Suppose you play a game in which 5 dice (6-sided) are rolled simultaneously.

goblinko [34]

The expected value of the game in which 5 dice (6-sided) are rolled simultaneously is -0.2094.

<h3>How to find the mean (expectation) and variance of a random variable?</h3>

Supposing that the considered random variable is discrete, we get:

Mean = $E(X) =$ $\sum_{\forall x_i} f(x_i)x_i$

Here, $x_i; \: \: i = 1,2, ... ,$ n is its n data values and $f(x_i)$ is the probability of $X = x_i$

Suppose you play a game in which 5 dice (6-sided) are rolled simultaneously.

If a "4" is rolled, then you win $2 for each "4" showing.
If all the dice are showing "4", you win $1000.
If none of the dice are showing "4", then you lose $5.

Let Y is the amount of money player won. The value of X can be,

$Y=2,4,6,8,1000,-5$

<h3>How to find that a given condition can be modeled by binomial distribution?</h3>

Binomial distributions consists of n independent Bernoulli trials. Bernoulli trials are those trials which end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

Suppose we have random variable X pertaining binomial distribution with parameters n and p, then it is written as

$X \sim B(n,p)$

The probability that out of n trials, there'd be x successes is given by

$P(X =x) = \: ^nC_xp^x(1-p)^{n-x}$

The expected value and variance of X are:

$E(X) = np\\ Var(X) = np(1-p)$

Put the values as 5 trials for each time 4 appears.

$P(X =0) = \: ^5C_1(\dfrac{1}{6})^0(1-\dfrac{1}{6})^{5-0}=0.4018 \:\\P(X =1) = \: ^5C_1(\dfrac{1}{6})^1(1-\dfrac{1}{6})^{5-1}=0.402\\P(X =2) = \: ^5C_2(\dfrac{1}{6})^2(1-\dfrac{1}{6})^{5-2}=0.162\\P(X =3) = \: ^5C_3(\dfrac{1}{6})^3(1-\dfrac{1}{6})^{5-3}=0.032\\P(X =4) = \: ^5C_4(\dfrac{1}{6})^4(1-\dfrac{1}{6})^{5-4}=0.0032\\P(X =5) = \: ^5C_5(\dfrac{1}{6})^5(1-\dfrac{1}{6})^{5-5}=0.00013\\$