You start by changing both the a common denominator, this case it would be 100 so it’s 2/100 and 5/100, since 1/50 and 2/100 is the same, each 1/100 is equal to “6” and you have 5/100, which is EQUAL TO 30
Answer:
y=x+1
Step-by-step explanation:
1) <u>Find the </u><u>slope</u>
m=-3-4/-4-3
m=-7/-7
m=1
2) <u>Use </u><u>y</u><u>=mx+</u><u>c</u>
<u>by </u><u>using </u><u>the </u><u>point </u><u>(</u><u>3</u><u>,</u><u>4</u><u>)</u>
<u>4</u><u>=</u><u>1</u><u>(</u><u>3</u><u>)</u><u>+</u><u>c</u>
<u>4</u><u>=</u><u>3</u><u>+</u><u>c</u>
<u>c=</u><u>1</u>
3) <u>The </u><u>answer</u>
y=x+1
Answer:
20%
Step-by-step explanation:
1. subtract the new price from the original price

2. divide the difference by the original number
÷ 

3. multiply this number by 100

2n + 28 = 96 [Two times n plus twenty-eight equals ninety-six.}
You need to get n by itself, so you first subtract 28 on both sides
2n + 28 - 28 = 96 - 28
2n = 68 Divide 2 on both sides
n = 34
Answer:
a) 
b) 
Step-by-step explanation:
For this case we can use a linear model to solve the problem.
s) Create an equation to express the increase on the price tickets and the number of seats sold
number of seats, if w analyze the info given the number of seats after increase the price is given by
.
And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.
We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

So then our linear equation is given by:

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?
So for this case we just need to replace the limits into the linear equation and see what we got:


So the corresponding range of ticket prices is:
