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djverab [1.8K]
2 years ago
12

Point E is located at (-5,2). Point M is the reflection of point E across the y-axis. What is the distance between E and M?

Mathematics
1 answer:
MArishka [77]2 years ago
4 0

Answer:

The distance is Ten

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Jill makes purses and backpacks. To make each purse,she uses 1foot less than half the amount of fabric she uses to make a backpa
nikklg [1K]

Answer:

Step-by-step explanation:

Jill makes purses and backpacks.

Let x represent the number of foot of fabric required to make a purse.

Let y represent the number of foot of fabric required to make a backpack.

To make each purse,she uses 1 foot less than half the amount of fabric she uses to make a backpack. This means that

x = (y/2) - 1

Therefore, the amount of fabric that Jill needs to make backpack will be

y/2 = x-1

y = 2(x-1) = 2x - 2

The number of feet of fabric that she will use to make a purse is

x = (y/2) - 1

4 0
3 years ago
Plz help Tysm if u do
Nastasia [14]

Just keep adding 1/6 to the given term and that should help you figure out the rule.

6 0
2 years ago
Read 2 more answers
How do you substitute 4(x) into the inequality 1/2x+5y-10<0 to find the possible value of y?
Veseljchak [2.6K]
You put 4 in the X
1/2(4)+5y-10<0
2+5y-10<0
-8+5y<0
5Y<8
Y<8/5
3 0
2 years ago
3. An airplane flies 105 miles in ½ hour. How far can it fly in 1 ¼ hours at the same rate of speed?
raketka [301]
262.5 miles
explanation 1/4 is half of 1/2 so 52.5 is half of 105 and then 210 for an hour of travel
5 0
3 years ago
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Un chip tiene un espesor de 0,12 mm y un atomo de cobre mide 0,00000000133 m.¿cuantos atomos se necesita para alinearlos en el e
aleksandr82 [10.1K]

Answer:

El espesor de un chip es de 0.12mm

Y el diámetro de un átomo de cobre, mide aprox:

0.00000000133 m

Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm

Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm

Primero, escribamos ambos valores en las mismas unidades, sabiendo que:

1m = 1000mm

Podemos reescribir:

0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm

Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm

Esto sera igual al cociente entre 0.12mm y  0.00000133mm, esto es:

N = (0.12mm)/(0.00000133mm) = 90,225.6

Redondeamos al próximo número entero:

N = 90,226

Esa es la cantidad de átomos que se necesitan.

7 0
3 years ago
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