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2 years ago

5

Slope is 2/3 y- intercept is -2

2 answers:

Naily [24]2 years ago

8 0

Answer:

$y = \frac{2}{3} x -2$

Step-by-step explanation:

This is the slope-intercept form. The slope-intercept form is written as y = mx + b where m is the slope and b is the y-intercept. The y and x stay as they are.

I hope this was what you were looking for.

Anarel [89]2 years ago

5 0

Answer:

y = (2/3)x - 2

Step-by-step explanation:

The equation of this line is y = (2/3)x - 2, where m is the given slope and -2 is the given y-intercept. We need only plug in the given values for m and b.

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Help please, need to show work.

stiks02 [169]

9514 1404 393

Answer:

3. m∠A < 80°

Step-by-step explanation:

The exterior angle NGS, marked as 80°, has a measure that is the sum of the measures of the remote interior angles: GAN, GNA.

If we assume that angle measures cannot be zero, then we must have ...

m∠A +m∠N = 80°

m∠A = 80° -m∠N

Since m∠N > 0, the measure of angle A must be less than 80°.

This conclusion matches choice 3.

8 0

2 years ago

Suppose the roots of the equation 2x^2−5x−6=0 are α and β.Find the quadratic equation with roots 1/α and 1/β.

pochemuha

Answer:

6x² + 5x - 2 = 0

Step-by-step explanation:

Given

2x² - 5x - 6 = 0 ← in standard form

with a = 2, b = - 5, c = - 6, then

sum of roots α + β = - $\frac{b}{a}$ = $\frac{5}{2}$

product of roots = $\frac{c}{a}$ = - 3, then

sum of new roots = $\frac{1}{\alpha }$ + $\frac{1}{\beta }$

= $\frac{\beta+\alpha }{\alpha \beta }$

= $\frac{\frac{5}{2} }{-3}$ = - $\frac{5}{6}$

product of new roots = $\frac{1}{\alpha }$ × $\frac{1}{\beta }$

= $\frac{1}{\alpha\beta }$ = - $\frac{1}{3}$

Hence the required equation is

x² + $\frac{5}{6}$ x - $\frac{1}{3}$ = 0 or

6x² + 5x - 2 = 0 ( multiplying through by 6 )

8 0

3 years ago

Find the total area for the regular pyramid.

hram777 [196]

Answer:

Option B

Step-by-step explanation:

Given is the hexagonal pyramid.

We know the radius of the base is same as its side.

<u>Find the base area:</u>

A = 3√3/2a²
A = 3√3/2*6² = 54√3

<u>Given the height and radius, find the side of the lateral triangular faces:</u>

$\sqrt{8^2+6^2} =\sqrt{100} =10$

Each of 6 triangles have sides 10, 10 and 6 units.

<u>Find the area using heron's formula:</u>

s = P/2 = (10*2 + 6)/2 = 13
s - a = s - b = 13 - 10 = 3
s - c = 13 - 6 = 7
$A = \sqrt{s(s-a)(s-b)(s-c)} =\sqrt{13*3*3*7} =3\sqrt{91}$

<u>Total surface area:</u>

$S = 6*3\sqrt{91}+54\sqrt{3} =18\sqrt{91}+54\sqrt{3}$

Correct choice is B

3 0

1 year ago

What are two equivalent equations for<br> x(5x-6)+13x-10

Naily [24]

5x^2 +7x -10

5x^2 (-6x + 13x) - 10

4 0

2 years ago

I need help please bsbshshhdbdbdbdbbdbdbfbdbdndn

Elden [556K]

Answer:

x is 3.4 i think

Step-by-step explanation:

8 0

2 years ago