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neonofarm [45]
4 years ago
12

What is 13 x 1 and 1/3

Mathematics
1 answer:
Molodets [167]4 years ago
7 0
13 x 1 1/3 = 17.3

Hope I helped :)
You might be interested in
The 12th term and the sim of 1+3+5+7+.....
zzz [600]

To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.

subtract 1 from 3

3-1=2

So each number is having 2 added to it.

Now add two to 7 and the numbers afterwards till you get the 12th term

7+2=9

1+3+5+7+9

9+2=11

1+3+5+7+9+11

11+2=13

1+3+5+7+9+11+13

13+2=15

1+3+5+7+9+11+13+15

15+2=17

1+3+5+7+9+11+13+15+17

17+2=19

1+3+5+7+9+11+13+15+17+19

19+2=21

1+3+5+7+9+11+13+15+17+19+21

21+2=23

1+3+5+7+9+11+13+15+17+19+21+23

So 23 is the 12th term


7 0
4 years ago
HELP ME PLEASE!!!!!!!!!!!
Angelina_Jolie [31]
Not linear .........
3 0
3 years ago
Someone help me with these two. I'll give you brainliest and 25 points!! MATHEMATICIANS OUT THERE HELP
mixer [17]
Hello LovingAngel!

To find the slope, you can use the formulas \frac{rise}{run} as well as \frac{y^2-y^1}{x^2 - x^1}. I am using the latter to calculate and ensuring my answer with the former. 

[Note: (x,y) is the format for ordered pairs]

First pair:  value 1:(1,5) and value 2:(2,8) 
\frac{y^2-y^1}{x^2 - x^1} -> \frac{8 - 5}{2 - 1} -> \frac{3}{1} or 3. 

The slope for (1,5) and (2,8) is 3(/1). 

Second pair: value 1: (3,1) value 2 (3,-1)

\frac{y^2-y^1}{x^2 - x^1} -> \frac{-1 - 1}{3 - 3} -> \frac{-2}{0}
Slope for the second pair is -2/0

Checking work with \frac{rise}{run}
1. Slope: 3/1, meaning rise (y) +3 and run (x) +1.  (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) <span>✔</span>

6 0
3 years ago
1) After striking a pair of arcs from each endpoint of a line segment, what is the next step in constructing the segment's perpe
qaws [65]
After striking a pair of arcs from each endpoint of a line segment, just join the intersection point of the 1st pair (above the segment) with the intersection point
of the 2nd pair (under the segment)
And this is how you construct the segment's perpendicular bisector


6 0
4 years ago
Read 2 more answers
Helppppppppppppppppppppppppppppppp
NemiM [27]
The first answer, subtract 6 from 27, then divide by 3
4 0
3 years ago
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