Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
_____
* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
<span>165/2
Hope this helps (:
</span>
We cant Answer it because the amount of cards presented is incorrect
Answer: X = 3t, Y =2 - t, Z =2
Step-by-step explanation: the plane
x + y + z =4has normal vector
M =<1,1,1> and the line
x = 1 + t, y = 2 − t, z = 2t has direction
v =<1, −1, 2>. So the vector
A= n × v
=<1, 1, 1> × <1, −1, 2>
=<2−(−1),1−2,−1−1>
=<3,−1,−2>
Okay. Since the "y" value and 82* are on the same straight line, their values will always add up to make a sum of 180. So if you subtract 82 from 180 you get 98*. So your "y" value is equal to 98*.
Now, all of the degree values added together should give you a sum of 360, so now we must add the values we know, in order to find the "x" value. So, 112*+82*+98*=292. Now we know that the difference of 360 and 292 will give us the x value. So finally, 360-292=68. So your "x" value is equal to 68.
y=98
x=68
