The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
Answer:
First one
Step-by-step explanation:
3s=5s-6
Answer: 
Step-by-step explanation:
Given the following equation:
You can follow these steps in order to solve for "x" and find its value:
1. Apply Distributive property on the right side of the equation:
2. Subract 
from both sides and add the like terms:
3. Subtract 1.8 from both sides:
4. Finally, divide both side of the equation by -1.5:
Looks like A is the answer.
