Answer:
![\dfrac{dx(t)}{dt} = kx(t)[1000-x(t)],$ x(0)=0](https://tex.z-dn.net/?f=%5Cdfrac%7Bdx%28t%29%7D%7Bdt%7D%20%3D%20kx%28t%29%5B1000-x%28t%29%5D%2C%24%20%20x%280%29%3D0)
Step-by-step explanation:
Total Number of People on Campus =1000
Let the number of people who have contracted the flu =x(t)
Therefore, the number of people who have not contracted the flu =1000-x(t)
Since the rate at which the disease spreads is proportional to the number of interactions between the people who have the flu and the number of people who have not yet been exposed to it.
![\dfrac{dx(t)}{dt} \propto x(t)[1000-x(t)]](https://tex.z-dn.net/?f=%5Cdfrac%7Bdx%28t%29%7D%7Bdt%7D%20%5Cpropto%20x%28t%29%5B1000-x%28t%29%5D)
Introducing the proportional constant k, we obtain:
![\dfrac{dx(t)}{dt} = kx(t)[1000-x(t)]](https://tex.z-dn.net/?f=%5Cdfrac%7Bdx%28t%29%7D%7Bdt%7D%20%3D%20kx%28t%29%5B1000-x%28t%29%5D)
At t=0, there was no infected on the campus, therefore the initial condition is given:
Therefore, a differential equation for the number of people x(t) who have contracted the flu is:
4 x 6 = 24 six times four is twenty four
Answer: The Answer is "less than"
Step-by-step explanation:
To find the sum of a series, you find the difference between the first and last term, multiply that by the number of terms, then divide by 2.
For the even numbers, 2 is the first term and 200 is the 100th term (because 2+(100-1)2 is equal to 200). So, (100(2+202)/2 = 10100.
For the odd numbers, 1 is the first term and 201 is the 101th term (because 1+(101-1)2 is equal to 201). So, (101(1+202))/2 = 10251.5.
10100<10251.5 so the sum of the first 100 even numbers is less than the sum of the first odd 101 numbers.
Answer:
y=√(4+x)(4−x)
Step-by-step explanation:
The equations woould look like this
a=2000(1+.0225/12) to the 12th power
b=2000(1+.03/12) to the 12th power
but i cant find the answer cuz i have no calculator sorry but i hope i still helped.
