The first five terms of the sequence are 1, 4, 7, 10, 13.
Solution:
Given data:


General term of the arithmetic sequence.
, where d is the common difference.
d = 3

Put n = 2 in
, we get



Put n = 3 in
, we get



Put n = 4 in
, we get



Put n = 5 in
, we get



The first five terms of the sequence are 1, 4, 7, 10, 13.
Hello!
The left triangle have two same side length so the two bottom angles are the same which is (180-56)/2=62
See the left triangle bottom right angle and the right triangle bigger angle have the sum of 180 degree so the bigger angle=180-62=118
The right triangle also have two same sides so they also have same angle degree so x=(180-118)/2=31
Have a great day!
What area of math is this,I may be able to help?
twice as many cats (as) dogs.
c = 2d [not true]
Three less than twice as many cats (as) dogs.
c = 2d - 3
210 combined,
c + d = 210
Subtracting,
-d = 2d - 3 - 210
-3d = -213
d = 71
Answer: 71
Answer:
11
Step-by-step explanation:
The two equations appear to be ...
- 12x +4y = 152
- 32x +12y = 420
These can be solved for y using Cramer's rule:
y = (152(32) -420(12))/(4(32) -12(12)) = -176/-16 = 11
The cost of the vegetarian lunch is 11.
_____
<em>Comment on Cramer's Rule</em>
For equations ...
ax +by =c
dx +ey = f
The solutions are ...
x = (bf -ey)/(bd -ea)
y = (cd -fa)/(bd -ea) . . . . note the denominators are the same expression
Once you memorize the pattern of products, this can be the simplest way to solve a pair of equations--especially if you only need one of the variable values.