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Leokris [45]
3 years ago
7

Consider the two functions:

Mathematics
1 answer:
Alik [6]3 years ago
6 0

Answer:

Step-by-step explanation:

1, Find (g-f)(x)

we know (g-f)(x) = g(x) - f(x) = ( 5x -2) -( 2x^2 +3x +6)

= 5x -2 - 2x^2 - 3x - 6

= -2x^2 + 2x -8

So the function (g-f)(x) = - 2x^2 + 2x - 8

2, Find (fg)(x)

we know that (fg)(x) = f(x) * g(x)

= (2x^2 +3x +6 ) *( 5x -2)

= 5x* (2x^2 +3x +6 ) - 2*(2x^2 +3x +6 )

= 10x^3 + 15x^2 +30x -4x^2 -6x - 12

= 10x^3 + 11x^2 + 24x - 12

The answer is (fg)(x)= = 10x^3 + 11x^2 + 24x - 12

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Enunciado:Si una empresa determina que sus costos obedecen a un modelo lineal y además sabe que si produce $10$ unidades sus cos
const2013 [10]

Responder:

y = 200x + 2000

Explicación paso a paso:

Deje que la ecuación lineal se exprese como y = mx + c

m es la pendiente

c es la intersección

Si la empresa produce $ 10 unidades, sus costos totales son $ 4000 dólares y si produce $ 15 unidades sus costos ascienden a $ 5000 dólares, entonces podemos representar esto como puntos de coordenadas;

(10,4000) y (15,5000)

Conseguir la pendiente

m = 5000-4000 / 15-10

m = 1000/5

m = 200

Obtener la intersección c

Sustituya m = 2000 y el punto (10, 4000) en la fórmula y = MX + c

4000 = 200 (10) + c

4000-2000 = c

c = 2000

Sustituya m = 200 y c = 2000 en la ecuación y = mx + c

y = 200x + 2000

Por tanto, la expresión lineal requerida es y = 200x + 2000

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Step-by-step explanation:

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