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Greeley [361]
4 years ago
13

A water bottle holds 5/8 L of water when it is 3/4 full which statement best describes a quotient of five eights divided by thre

e fourths
Mathematics
1 answer:
stellarik [79]4 years ago
7 0

Answer:

The maximum amount the bottle can hold is  litre.

Step-by-step explanation:

To find out how much water is in 1 bottle, the amount of litres can be divided  by three to find out how much water is in one quarter of the bottle. Th amount can then be multiplied by four, to to find the volume of one bottle

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Solve for y.<br> 3x-4y=6<br> Explain please!
Snezhnost [94]
So 3x=6+4y
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4 years ago
Benjamin has a mask collection. He keeps 144 of the masks on his wall, which is 48% of his entire collection. What is the total
Harman [31]

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213

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4 0
3 years ago
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Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d)​, one of which is co
arlik [135]
A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

P(C) = \frac{1}{4}

The probability of choosing wrong answer is

P(W) = \frac{3}{4}

Using the multiplication rule
P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

WWC

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

WCW

Or the first one is correct and the last two are wrong. This will give the arrangement,

CWW
.

P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}

P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64}  \\ \\ P(One \: Correct) = \frac{27}{64}
7 0
4 years ago
Read 2 more answers
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