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3 years ago

12

The table shows the scoresof 20 students in a test, work out the mean score

1 answer:

adoni [48]3 years ago

7 0

Answer:

2.7

Step-by-step explanation:

hope you understand if you don't understand tell me I'll try again.

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Determine which function(s) is not a linear function. Select all that apply.

olganol [36]

The answers are a, c, d, e

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3 years ago

Read 2 more answers

Find the surface area of the shape below. Answer in NUMBERS only, NO units. Round your answer to the nearest tenth.

Vilka [71]

Step-by-step explanation:

In the given figure, its a cube with edge 7.7 inches.

Surface area = 6a²

Where ‘a’ denotes the edge

→ 6(7.7)²

→ 6 × 59.29

→ 355.74

Rounding nearest tenth :

→ 355.8

6 0

3 years ago

-6(1 + 2x) + 6x = 6(-3x - 3)

Maksim231197 [3]

Answer:

x = - 1

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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7 0

3 years ago

A point K is on the perpendicular bisector of a segment with endpoints at H and J. What must be true about point K? It is equidi

kykrilka [37]

Answer:

$K$ is equidistant from $H$ and $J$ .

Step-by-step explanation:

Given that the point $K$ which is on the perpendicular bisector of the line segment having endpoints at $H$ and $J$ .

The given situation can be represented as the diagram as attached in the answer area.

Referring to the $\triangle HOK, \triangle JOK$ :

$\angle HOK = \angle JOK=90^\circ$ (As it is the perpendicular bisector)

$OH = OJ$ (As it is the perpendicular bisector)

Also, the side $OK$ is the common side.

Therefore by $S-A-S$ congruence, $\triangle HKO\cong \triangle JKO$

As per the properties of congruent triangles:

Side $HK$ = Side $JK$

$HK$ and $JK$ are nothing but the distance of the point $K$ from the end points $H$ and $J$ which are proved to be equal to each other.

Therefore, we can conclude that:

$K$ is equidistant from $H$ and $J$ .

5 0

3 years ago

One factor of the function f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5) Describe how to find the x-intercepts and the y-intercept o

pickupchik [31]

Answer:

x-intercept(s): (−1.9900717, 0)

y-intercept(s): (0, 52.5)

Step-by-step explanation:

To find the x-intercept, substitute in $0$ for $y$ and solve for $x$ . To find the y-intercept, substitute in $0$ for $x$ and solve for $y$ .

$f(x)=y$

$(x)=x$

<u>x-intercept</u>

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5$

$=\bold{0}=x^3-8x^2+17x-10.5\left(x-5\right)$

$=0\cdot \:10=x^3\cdot \:10-8x^2\cdot \:10+17x\cdot \:10-10.5\left(x-5\right)\cdot \:10$

$=0=10x^3-80x^2+170x-105\left(x-5\right)$

$=0=10x^3-80x^2+65x+525$

$=10x^3-80x^2+65x+525=0$

$=10x^2-99.90071\dots x+263.80959\dots \approx \:0$

$\bold{x\approx \:-1.99007\dots}$

<u>y-intercept</u>

$f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5$

$=y=\bold{0}^3-8(\bold{0})^2+17(\bold{0})-10.5\left(\bold{0}-5\right)$

$=y=0-8\cdot \:0+17\left(0\right)-10.5\left(0-5\right)$

$=y=0-8\cdot \:0+17\cdot \:0-10.5\left(0-5\right)$

$=y=0-0+0-\left(-52.5\right)$

$=0-0+0+52.5$

$\bold{y=52.5}$

8 0

2 years ago