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trapecia [35]
2 years ago
9

a telephone technician charges $30 per hour plus a $45 service charge your father's firm hires him to hook up his company's phon

e system find the total charges if it takes the telephone technician 6.5 hours to complete the task
Mathematics
1 answer:
hodyreva [135]2 years ago
6 0

y=mx+b

y=30h + 45

h= 6.5h

y=30(6.5)+45

y=$240

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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
A) 2(x+3)=x-4 <br>Could anyone help?​
oee [108]
If solving for x you will first need to combine like terms. Then after getting the amount of numbers and amount of x numbers you will divide the x number from both. After doing that you would get X=-10
7 0
2 years ago
If you stacked Avogadro's number of pennies one on top of the other on Earth's surface, how far would the stack extend (in kilom
miskamm [114]

Answer:my

The height of the stack will be 9.15×10^20_m

Or 9.15×10^17_Km

Which is 6 billion times more more than the distance to the sun

Or 22.9 million times further than the star Proxima Centauri

Step-by-step explanation:

Given

Avogadro's number = 6.02×10^23 particles

And the thickness of a penny = 1.52_mm

The height of the stack will be

1.52 × 6.02 ×10^23 = 9.15×10^23_mm 9.15×10^20_m

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3 years ago
Which of the following is true?
Dahasolnce [82]

Answer:

the right ones are a c and d maybe

Step-by-step explanation:

these are probably wrong but I need my points so figure it out.

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2 years ago
At a school for performance art students 2
gtnhenbr [62]

Answer:

i need help with this too

Step-by-step explanation:

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