100-45+22= 77
you will have 77 percent of battery on your phone
The answer to this question is A, 12. Hope this helps.
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614
Answer:
0.59375
Step-by-step explanation:
3f(x) - f(1/x) = x^2
x = 2: 3f(2) - f(1/2) = 2^2
x = 1/2: 3f(1/2) - f(2) = (1/2)^2
Let a = f(1/2) and b = f(2):
3b - a = 4; 3a - b = 1/4
3b - 4 = a
3(3b-4) - b = 1/4
8b = 12 + 1/4
b = 1.53125
3 * 1.53125 - 4 = a
a = 0.59375
The formula is there for area of a trapezoid.
1/2(4)(9 + 13)
2(22)
44
