1MB=1000 kb
≈ 1748,71 seconds
ransform in kilobyte and share knowing transfer time :)
Answer:
Create a dynamic-sized circularly-linked list to hold a tuple of the adverts and the count. As the program runs, the sum of the counts is used to calculate the fixed advertisement time which is saved in a variable time_slot. Then a loop statement should be used to traversal the linked list continuously until the count sum is exhausted for the day.
Explanation:
A circularly-linked list is a linked list with both ends joined together. With this data structure, the continuous traversal of the list is easier and faster. A conditional statement is used in the algorithm to check and decrement the count of each advert and when all is zero or false, the program ends.
Answer:
#include <iostream>
using namespace std;
void MinMax(int x,int y,int z,int *max,int *min)
{
int big,small;
if((x>y)&&(x>z)) //to check for maximum value
big=x;
else if((y>x)&&(y>z))
big=y;
else
big=z;
if((x<y)&&(x<z)) //to check for minimum value
small=x;
else if((y<x)&&(y<z))
small=y;
else
small=z;
*max=big; //pointer pointing to maximum value
*min=small; //pointer pointing to minimum value
}
int main()
{
int big,small;
MinMax(43,29,100,&big,&small);
cout<<"Max is "<<big<<"\nMin is "<<small; //big and small variables will get value from method called
return 0;
}
OUTPUT :
Max is 100
Min is 29
Explanation:
When the method is called from first three integers maximum will be found using the conditions imposed and maximum value will be found and similarly will happen with the minimum value.
It is the last one retention because writing it out will cause it to stick in your brain better
Because to prevent MITD (Man in the middle is a man that in the middle of the network. For example: You are sending a text, the man in the middle or in the modem will receive the text and can edit it and send it to the receiver, or the man will put the virus in...) and to prevent server snooping
