A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.
Answer: The correct option is B) about 34%
Proof:
We have to find 
To find , we need to use z score formula:
When x = 4.2, we have:
When x = 5.1, we have:
Therefore, we have to find 
Using the standard normal table, we have:
= 
or 34.13%
= 34% approximately
Therefore, the percent of data between 4.2 and 5.1 is about 34%
Answer:
Hi there!
The correct answer to this question is: yes.
Step-by-step explanation:
<u>standard form</u> means that the terms are ordered from biggest exponent to lowest exponent.
Answer:
Step-by-step explanation:
the perimeter of a square that has a side of (4x-3) is ; 4(4x-3) = 16x-12
Answer:n= 1/3d - 2/3m
Step-by-step explanation:
d=2m+3n
Step 1: Flip the equation.
2m+3n=d
Step 2: Add -2m to both sides.
2m+3n+−2m=d+−2m
3n=d−2m
Step 3: Divide both sides by 3.
3n/3 = d-2m/3
Therefore
n= 1/3d - 2/3m
Hope this helps!
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Answer:
n = d - 2m
3*
Step-by-step explanation:
First we want to get n alone on one side, so we should subtract 2m from both side;
d = 2m + 3n
3n = d - 2m
Now to get n by itself, we need to divide by 3 from both sides;
3n = d - 2m
n = d - 2m
3*
*Pretend there is a fraction bar between d - 2m and 3
Step-by-step explanation:
Answer:
The mean would be $322,343 and the median would be $196,723.
Step-by-step explanation:
Since the distribution of individual incomes is skewed to the right, it means that the distribution has a long right tail.
Drawing a distribution with this characteristic, we can see how the majority of the data falls into the left side of the graphic, meaning that a lot of people receive less income. Following this reasoning, the mean which is the amount of the data (in this case individual income) divided by the amount of people, would be the higher number, meaning that the few people who earn more money would influence in making this number higher.
Following this reasoning, the median (which is not influenced by this difference) would be the less high number.
