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puteri [66]
3 years ago
15

Which of these four sets of side lengths will form a right triangle?

Mathematics
2 answers:
Yuri [45]3 years ago
6 0

Answer:

Set 3

Step-by-step explanation:

If you square 3 mm and 4 mm then add them together you get 25 mm, then you get the square root of 25, which is 5.

natka813 [3]3 years ago
4 0

Answer:

set 2

Step-by-step explanation:

i just took the quiz on edge

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If A line has a y -intercept of 10 and a slope of 4 . What is its equation in slope -intercept form
chubhunter [2.5K]

Answer:

<h2>          y = 10x + 4</h2>

Step-by-step explanation:

The equation of a line in slope-intercept form is: y = mx + b, where <em>m</em> is a slope and<em> b</em> is y-intercept.

m = 10

b = 4

So, the equation:  y = 10x + 4

6 0
3 years ago
What is the equation of the line parallel to the line with the equation −x+3y=−3
mezya [45]

Answer:

y = 1/3x - 19/3

Step-by-step explanation:

3y = x -3

y = 1/3x -3

Slope = 1/3

Point= (1,-6)

y-intercept = -6 - (1/3)(1) = -6 - 1/3 = -19/3

5 0
2 years ago
In 2004, a pine tree was 5 3/4 ft tall. If the tree grew at an average rate of 5/6 ft per year for the next 7 years, how tall wo
Nady [450]

Answer:

11 7/12 ft tall

Step-by-step explanation:

5 3/4 + (5/6*7)

139/12

11 7/12

7 0
3 years ago
Pythagorean Theorem Word
diamong [38]

Answer:

40 miles

Step-by-step explanation:

In the attached diagram, Point A is the starting point and C is the end point. We want to determine the distance from A to C.

The path driven forms a right triangle in which AC is the hypotenuse.

We therefore use the<u> Pythagorean Theorem</u> to solve for the AC.

Pythagorean Theorem: Hypotenuse^2=Opposite^2+Adjacent^2

|AC|^2=32^2+24^2\\|AC|^2=1600\\|AC|=\sqrt{1600}\\ |AC|=40$ miles

The  straight  line distance from the starting point is 40 miles.

7 0
3 years ago
Find all solutions in the integers of the equation ||x−3|−5| = 10, where the bars indicate absolute value.
Helga [31]

Answer:

x = 18 or x = -12.

Step-by-step explanation:

||x-3|-5| = 10 only if |x-3|-5 = 10 or |x-3|-5 = -10, i.e., if |x-3|=15 or |x-3|=-5; but |x-3| cannot be equal to -5, because |x-3| should be a non-negative value. Therefore, the first equation is true only if |x-3|=15. |x-3| = 15 only if x-3 = 15 or x-3 = -15, i.e., x = 18 or x = -12.  We can verify this in the following way: ||18-3|-5|=||15|-5|=|10|=10 and ||-12-3|-5|=||-15|-5|=|15-5|=|10|=10. This verify that our solution is correct.

3 0
3 years ago
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