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3 years ago

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Question 19 I know the answer is 1.5 but how

1 answer:

katrin2010 [14]3 years ago

5 0

Suppose the width of the path is x.
the dimensions of the extended rectangle are (12+x+x), and (16+x+x)
(12+2x)(16+2x)=285
4x²+56x+192=285
4x²+56x-93=0
Not easy to factor it, so use the quadratic formula to solve:
x={-56+√[(56²-4*4*(-93)]}/2*4 or x={-56-√[(56²-4*4*(-93)]}/2*4
x=1.5 (ignore the negative solution.)

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Alright, Since my previous questions have not been answered, here's 50p to whoever solves this

BigorU [14]

Step-by-step explanation:

We can make 2 equations as follows:

2x = y + 16 and x + 2y = 18

x + 2y = 18 is the same as x = 18 - 2y. Hence, 2(18 - 2y) = 2x = y + 16.

2(18 - 2y) = y + 16

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3 years ago

Which expresses 216:270 in its simple form

Ivanshal [37]

Answer:

4/5

Step-by-step explanation:

Steps to simplifying fractions

Find the GCD (or HCF) of numerator and denominator

GCD of 216 and 270 is 54

Divide both the numerator and denominator by the GCD

216 ÷ 54

270 ÷ 54

Reduced fraction:

4

5

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3 years ago

Six less than the product of five and a number is ten.

dlinn [17]

The answer is 5 because it would like that’s

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3 years ago

There exist two complex numbers $c$, say $c_1$ and $c_2$, so that $3 + 2i$, $6 + i$, and $c$ form the vertices of an equilateral

leva [86]

Answer:

The answer is " $\sqrt{12.5}$ "

Step-by-step explanation:

$\to (3,2), \ (6,1)$

Distance $=\sqrt{9+1}=\sqrt{10}$

midpoint height $=\sqrt{10+2.5}=\sqrt{12.5}$

let

Gradient $= \frac{1}{-3}$

Perpendicular Gradient $= 3$

midpoints $= (4.5, 1.5)$

Similar to perpendicular

Now I'll obtain the perpendicular bisector solution

An equation of the center circle $(4.5,1.5)$ radius will be $\sqrt{12.5}$ .

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3 years ago

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xenn [34]

(2, -3)

The Answer is A

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3 years ago