Answer:
(-1.6, 0)
(0, 0.8)
Step-by-step explanation:
I know this doesn't really help but... Good luck on the test!! And also I'm pretty sure they have youtube vids on how to do this stuff. Well, anyway bye!!! Good luck!!!
Answer:
m = 2/3
y-intercept: 2
Explanation:
First convert this equation into standard form by distributing the 6y and -4x from the coefficient of 2, and then putting the variables in order.
This equation should be in the form: Ax + By = C (Standard form)
y = -Ax/B + C/B : y = mx + b (Slope intercept form)
2(6y - 4x) = 24 → 12y - 8x = 24
→ -8x + 12y = 24 → -8x = -12y + 24 → 8x = 12y - 24 → <em>8x - 12y = -24</em>
<u>8</u>x <u>- 12</u>y = <u>-24</u>
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A B C
Once you have standard form, you are ready to convert this into slope intercept by isolating the y completely.
8x - 12y = -24
-8x -8x
(First through the subtraction property of equality, remove 8x from both sides so that -12y is by itself on the left)
-12y = -8x - 24
×-1 ×-1 ×-1
(Through the identity property of negative 1, remove the negative sign from all of the numbers because a negative times a negative is a positive)
12y = 8x + 24
(Lastly, through the division property of equality, divide all sides by 12 because it is the coefficient of y, which will solve for the variable)
1) We can determine by the table of values whether a function is a quadratic one by considering this example:
x | y 1st difference 2nd difference
0 0 3 -0 = 3 7-3 = 4
1 3 10 -3 = 7 11 -7 = 4
2 10 21 -10 =11 15 -11 = 4
3 21 36-21 = 15 19-5 = 4
4 36 55-36= 19
5 55
2) Let's subtract the values of y this way:
3 -0 = 3
10 -3 = 7
21 -10 = 11
36 -21 = 15
55 -36 = 19
Now let's subtract the differences we've just found:
7 -3 = 4
11-7 = 4
15-11 = 4
19-15 = 4
So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.
3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2
