How do I solve for X

Which expression has exactly three terms? Select all the expressions that apply.

irga5000 [103]

The answer is expressions D, E, and G.

In algebra, a ‘term’ usually means the different parts of an expression that are separated by + and - signs.

Options A and B only have 1 term, an x or y³, so these are incorrect.

Option C has 1 term as well, ‘xyz’, because they are all multiplied together which makes it one term.

D and E both have 3 terms each, but F has 4 unique terms so this is incorrect also.

G has 3 unique terms, x³, x^4, and 7x, so this is correct.

When H is expanded, you will end up with more than 3 unique terms, so this is incorrect.

I hope this helps!

6 0

3 years ago

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Simplify the expression. 2.5-5.5n - 3n + 6

Snowcat [4.5K]

simplified, it should be -8.5n+8.5

8 0

2 years ago

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PLEASE HELP ME GUYS OR I WONT PASS this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle H(x) = \sqrt[3]{F(x)}$

Step 2: Differentiate

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

Step 3: Evaluate

Substitute in x [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago

Craig is folding laundry for his family. in the basket 1/6 of the shorts belong to his older brother and 3/6 of the shirts belon

marishachu [46]

I'm assuming you meant shirts instead of shorts for the older brother.

1/6 + 3/6 = 4/6

4/6 of the shirts belong to his brothers
(or 2/3 if you simplify the fraction)

5 0

3 years ago

Which is an x-intercept of the graphed function? O(0, 4) 0 (-1.0) Q (40) (0,-1)

NISA [10]

Answer:idk just here for the points

Step-by-step explanation:

6 2

3 years ago

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