Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
The answer to 14+(-2) is 12
<span>(3, 4.5) and (3, 3)
The midsegment of a triangle is a line connecting the midpoints of two sides of the triangle. So a triangle has 3 midsegments. Since you want the midsegment that's parallel to LN, we need to select the midpoints of LM and MN. The midpoint of a line segment is simply the average of the coordinates of each end point of the line segment. So:
Midpoint LM:
((0+6)/2, (5+4)/2) = (6/2, 9/2) = (3, 4.5)
Midpoint MN:
((6+0)/2, (4+2)/2) = (6/2, 6/2) = (3, 3)
So the desired end points are (3, 4.5) and (3, 3)</span>
Answer:
The probability that the sample will contain exactly 0 nonconforming units is P=0.25.
The probability that the sample will contain exactly 1 nonconforming units is P=0.51.
.
Step-by-step explanation:
We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.
We can write the probability mass function as:
where k is the number of non-conforming units on the sample of n=4.
We can calculate the probability of getting no non-conforming units (k=0) as:
We can calculate the probability of getting one non-conforming units (k=1) as:
Answer:
100/100'000*5 = 5000 + base commission of 100'000 = 105'000
Step-by-step explanation:
