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bogdanovich [222]
3 years ago
11

Five binders and three folders cost $23. Five binders and one folder cost $20. How much does one binder cost?

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0

Answer:

one binder for $3.70

Step-by-step explanation:

The cost of 5 binders and 3 folders = $23.00

The cost of 5 binders and 1 folder = $20.00   [ 2 folders less ]

Cost of 2 folders = 23 - 20 = $3.00

Cost of 1 folder = \frac{3}{2} = $1.50

The cost of 5 binders = 20.00 - 1.50 = $18.50

The cost of 1 binder = \frac{18.50}{5}

                                = $3.70

The cost of one binder is $3.70

riadik2000 [5.3K]3 years ago
5 0

Answer: $3.7

Step-by-step explanation:

23-20=3

3/2=1.5

20-1.5=18.5

18.5/5=3.7

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tensa zangetsu [6.8K]

<u>The given options are:</u>

(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

(B)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector.

(C)the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector.

(D)the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.

Answer:

(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

Step-by-step explanation:

The area of the shaded sector can be determined using the formula:

\frac{m\angle ZYX}{360^\circ} \cdot \pi r^2

m\angle XYZ=$Central angle of XYZ\\\pi r^2$=Area of a Circle

360^\circ =$Total Angle

Therefore, the formula is:

\dfrac{m\angle ZYX}{360^\circ} \cdot \pi r^2\\\text{Area of XYZ}=\dfrac{\text{Cental Angle of XYZ}}{\text{Total Angle}} X \text{Area of the Circle}

Therefore, the formula is best explained by Option A.

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3 years ago
If f(3)=2x^3 -2 , what is the value of f(2)
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I'm not sure about this but will give it a try:

Let f(n) = 2xⁿ - 2

Then f(3) = 2x³ - 2

So, f(2) = 2x² - 2

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ABCD is a quadrilateral with A(8,21),B(10,27),C(26,26) and D(18,2). Determine whether ABCD is a trapizoid
Svetradugi [14.3K]
<h2>Answer:</h2>

ABCD is a trapezoid

<h2>Step-by-step explanation:</h2>

<em>Given points of the quadrilateral:</em>

A(8,21),B(10,27),C(26,26) and D(18,2)

To show whether ABCD is a trapezoid, we find a pair of parallel sides in ABCD. If two of its sides are parallel to each other then ABCD is a trapezoid.

<em>Step 1:</em> With the given points, sketch a graph. The diagram is attached to this response.

<em>Step 2:</em> As shown in the diagram, the two sides that are likely to be parallel are AB and CD

If these two sides have same gradient/slope, then the quadrilateral is a trapezoid.

Now calculate the slopes of those sides using the slope formula;

m = \frac{y_2 - y_1}{x_2 - x_1}

<em>Calculate the slope of AB </em>(where x₁ = 8, y₁ = 21, x₂ = 10, y₂ = 27)

m(AB) = \frac{27-21}{10-8}

m(AB) = \frac{6}{2}

m(AB) = 3

<em>Calculate the slope of CD </em>(where x₁ = 26, y₁ = 26, x₂ = 18, y₂ = 2)

m(CD) = \frac{2-26}{18-26}

m(CD) = \frac{-24}{-8}

m(CD) = 3

Since the two slopes - m(AB) and m(CD) slopes are equal to 3, the quadrilateral ABCD is a trapezoid.

5 0
3 years ago
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