Answer:
The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08
Step-by-step explanation:
To solve this exercise we have to know that the probability is calculated by dividing the number of favorable events by the number of possible events.
f = favorable events
we will count how many numbers between 1 and 50 have the same number in the ones place in the tens place
11 ; 22 ; 33 ; 44
as we can see there are 4 numbers
f = 4
p = possible events
the number of possible events is given by the number of cards in the deck
p = 50
4/50 = 0.08
The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08
Order of Operations, also known as PEMDAS (Parentheses, Exponents, Multiplication & Division, Addition & Subtraction), can help to simplify an equation by guiding you through the steps to solve it.
This is because it tells you to solve the parentheses. If there is none, but you've already done this, you solve for exponents, etc.
The progressive soling of the equation not only makes it physically shorter, but also brings you closer to the answer.
Hope this helps, and I was the brainliest! :)
Answer: 2 times sqrt(181) (approximately 26.9)
Step-by-step explanation:
First, we can plot these points on a graph. Then, we’ll use the Distance Formula to calculate the distance between the two points, which is sqrt(181).
Since the problem tells us that one of our coordinates is the midpoint of K, we know that the length of the segment we just calculated is 1/2 of K. We can multiply our answer to get that K is 2 times sqrt(181).
31 1\4% as a fraction is 31x4+1 over 4
125\4 %
Answer:
60
Step-by-step explanation:
65% = .65, so
60 × .65 = 39
or the equation could be
60/.65 = x
Hope this helps, if not please let me know and i will do my best to correct my mistake.
