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3 years ago

11

I go to school on the 4th of June Monday and i summer term is on 29th June i have 3 days a week at school Monday Tuesday Wednesd

ay
how meany of my schooldays are left

1 answer:

Virty [35]3 years ago

3 0

11 school days are left.

In the attached picture of a calendar, I marked the days the person has left. There are 11.

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3(x+7)+12x-7(x+1)+9-4x<br> Need answer and explaintion

seraphim [82]

Answer:

4

x

+

23

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP ME ON THIS

cricket20 [7]

The answer is 96. just multiply 6 *2 =12*2=24*2=48*2=96

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4 years ago

Read 2 more answers

4 3/4 X 4 1/7 what is it please help

Y_Kistochka [10]

first you turn the fractions into inproper fractions by multiplying the whole number by the denomonator and adding the numerator

4×4=16

16+3=19

19/4

4×7=28

28+1=29

29/7

keep the denomonators the same. now that you've converted them into inproper fractions you can multiply them

19/4 × 29/7=551/28

there is no way to simplify this answer so this is the final answer

7 0

3 years ago

How do i find B with a table??

Artist 52 [7]

B is the Y-intercept or where the graph crosses the y-axis. they provide you with a few things which can help you figure this out. they give you the values of x and y in a table
X | Y
2 | -5
4 | -9 The difference between each Y value is 4...so, I add 4 to the -5
6 | -13 and get -1...going up another value for the X would be at 0. This leaves me with an ordered pair of (0,-1).....thus, the value of b is -1.

4 0

3 years ago

Write a rule for the nth term of the arithmetic sequence:<br><br> a11= 50, d = 7

ivolga24 [154]

Answer:

Required rule for $n^{th}$ is $a_{n}=7n-27$ .

Step-by-step explanation:

Given that,

$a_{11} = 50,\ \ d=7$

From the question: we have to write the $n^{th}$ term of Arithmetic sequence.

Arithmetic Sequence or Arithmetic progression (A.P) : It is a sequence which possess that difference between of two successive sequence is always constant.

$a_{1} ,a_{2},a_{3},a_{4}.....................a_{n-1},a_{n}$

where, $a_{1}$ is the first term of A.P

$d$ is the common difference.

$a_{n}$ is the last term or general term.

The above sequence to be in A.P then their common difference should be equal.

$d=a_{2}-a_{1} =a_{3}-a_{2}=a_{4} -a_{3} ..........................a_{n}-a_{n-1}$

Now, Formula of General Term is $a_{n}=a+(n-1)d$

So, $a_{11}= a+(11-1)d\\ a_{11} = a+10d$

Substituting the value of $a_{11} = 50,\ \ d=7$ we get,

$50=a+10\times7\\50=a+70\\a=-20$

Then General term ( $a_{n}$ ) of given data is

$a_{n}=-20+(n-1)7\\a_{n}=-20+7n-7\\a_{n}=7n-27$

Therefore, Required rule for $n^{th}$ is $a_{n}=7n-27$ .

5 0

4 years ago