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Crank
2 years ago
15

Please answer this question correctly​

Mathematics
1 answer:
marissa [1.9K]2 years ago
7 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The required division equation will be :

  • \boxed{dividend = divisor \times quotient + remainder}

  • 52556 = 137 \times 383 + 85
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JulsSmile [24]

We know that there is a total of 900 cells, and 37 of the samples 60 are red. 900/60 is our unit rate of 15. 37 times 15 is 555. We will see 555 red blood cells in all of the cells.

555 is our answer.

Please forgive any typeos because I did this on my phone.

4 0
3 years ago
3+4x+x^2 = y Given x = 1
e-lub [12.9K]

Answer:

8

Step-by-step explanation:

4 0
3 years ago
Find the inequality represented by the graph.<br> Can someone please help me!!!!!!
lapo4ka [179]

Answer:

y

Step-by-step explanation:

We first need to determine the equation of the line.

Thus, we will need to find our slope first. To do so, we need to pick two points from the line. We can use (0, 5) and (3, 1).

Now, we can use the slope formula. Therefore:

m=\frac{y_2-y_1}{x_2-x_1}

Let (0, 5) be (x₁, y₁) and let (3, 1) be (x₂, y₂). Substitute appropriately:

m=\frac{1-5}{3-0}=\frac{-4}{3}

Therefore, our slope is -4/3.

Now, we can use the slope-intercept form:

y=mx+b

Where m is our slope and b is the y-intercept.

We already determined that the slope is -4/3.

And (0, 5) tells us that the y-intercept is 5. Therefore, substitute:

y=-\frac{4}{3}x+5

Finally, we need to determine our inequality sign.

Notice that our line is dotted. Hence, we do not need “or equal to.”

Also, the blue shaded region is below our line. Therefore, y must be less than our equation.

Hence, our sign is less than.

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y

8 0
3 years ago
The weight of
raketka [301]
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8 0
3 years ago
An oil tank is leaking into a lake at a rate of 0.1 m3/day. The oil slick forms a semicircular disk whose center is at the leak
gregori [183]

Answer:

17.9  m/s

Step-by-step explanation:

Volume of the slick =  0.5 x π r² h--------------------------------- (1)

Where r = radius of slick

           h = thickness of slick, 10⁻⁶m

If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)

V  =  0.5 x π r² h

0.5=  0.5 x  π x  r² x 10⁻⁶

r²   =  10⁶/ π

r =     10³/√π

dV/dt =   πrh dr/dt  + 0.5π r² dh/dt----------------------------------- (2)

Asumming the film thickness is constant , equation (2) becomes

dV/dt =   πrh dr/dt-------------------------------- (3)

dV/dt = 0.1m³/day

r=  10³/√π

dr/dt= rate of expansion of the slick

Substituting  into (3);

0.1 =  π x 10³/√π x 10⁻⁶ x dr/dt

dr/dt = 0.1  x 10⁶/ ( π x 10³/√π)

       =  17.9479 m/s

       ≅  17.9  m/s

8 0
3 years ago
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