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liubo4ka [24]
3 years ago
9

Find the product........................................

Mathematics
1 answer:
Verdich [7]3 years ago
8 0

For this case we must find the product of (2x + 3) (2x-3), for this, we must apply the distributive property, which by definition establishes that:

(a + b) (c + d) = ac + ad + bc + bd

So:

(2x + 3) (2x-3) = (2x) ^ 2 + (2x) (- 3) + (3) (2x) + (3) (- 3)

considering that+ * - = -

(2x + 3) (2x-3) = 4x ^ 2-6x + 6x-9\\(2x + 3) (2x-3) = 4x ^ 2-9

Answer:

Option A


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Evaluate the expression for s = 0
nikklg [1K]

The evaluation of the expression is S equals zero

5 0
3 years ago
A town in east Texas received 30 inches of rain in two weeks. If it kept raining at this rate for a 31−day month, how much rain
anyanavicka [17]

Answer:

66 inches

Step-by-step explanation:

This implies that in this specific town in Texas, an average of 30 inches of rain falls every two weeks.

Amount of rain received every two weeks (14 days) = 30 inches.

For a 31 day month, we have:

     \frac{31}{14} =  2\frac{3}{14}

Therefore for a 31 day month, the amount of rain received by the town can be determined as;

                               = 30 x 2\frac{3}{14}

                               = 66.4285

                               = 66 inches

The amount of rain received by the town is 66 inches for the 31 days.

5 0
3 years ago
Read 2 more answers
Round 52961 to one significant figure
Aneli [31]

Answer: 50000

Step-by-step explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.

All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.

All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.

All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.

Thus 52961 when rounded off to one significant figure will be 50000.

7 0
3 years ago
Lisa wants to use her calculator to square a two-digit positive integer, but she accidentally enters the tens digit incorrectly.
Svetradugi [14.3K]

Answer: Correct two digit number= 24

Step-by-step explanation:

Let

x= tens digit (wrong one)

and y= zeroes digit

and z= tens digit (right one)

Now according to the statement,

(10x+y)² -  (10z+y)² = 2340

Simplifying this we get

(x-z)(5x+y+5z)= 117= 1 * 3 * 3 * 13

So it could either be

x-z=1 or x-z=3

If we take the x-z=1

then 5x+y+5z=117

which is not possible as maximum value we can get from this is 99.

This leaves us with x-z=3

so 5x+y+5z= 39

Put x=3+z

We get,

y+10z= 24

Now as y and z both are single digits so the only possible numbers to fit these are y=4 and z=2.

Put z=2 in x=3+z , we get x=5

So the numbers become 10x+y= 54

and 10z+y= 24

Their sum is 54+24=78

Check

54²-24²= 2340 so it is correct.

7 0
3 years ago
Is algebra.
alexgriva [62]

Answer:

x = -11/7

x = 11/7

Step-by-step explanation:

49x² - 121

Factor

(7x + 11)(7x - 11)

roots

x = -11/7

x = 11/7

8 0
3 years ago
Read 2 more answers
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