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sesenic [268]
3 years ago
11

PLEASE HELP ASAP NUMBER 8 AND 9 SHOW WORK AND I WILL GIVE BRAINLIEST

Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

question 8

Step-by-step explanation:

y = 4

2x + 3y = 22

put y = 4 into equation 2

2x + 3 ( 4) = 22

2x + 12 = 22

2x = 22 - 12

2x = 10

x = 5

therefore x = 5 and y = 4

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stellarik [79]
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What is the area of the triangle?<br> 6<br> 2<br> 3
Llana [10]

Answer:

6

Step-by-step explanation:

Find the area of both triangles inside the bigger triangle and add them together.

Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:

a² + b² = c²

2² + b² = 3²

4 + b² = 9

5 = b²

2.2 ≈ b

Calculate the area of the smaller triangle:

1/2(bxh)

1/2(2 x 2.2)

1/2(4.4)

2.2

Calculate the area of the bigger triangle:

<em>We know that the longer leg is 3.8 units because we were able to subtract the length of the smaller triangle's leg from 6. </em>

1/2(bxh)

1/2(2 x 3.8)

1/2(7.6)

3.8

Add both areas to find the area of the largest triangle:

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7 0
3 years ago
The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27
Naddik [55]
ANSWER
3\pi sq.\: in.

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

R:r=3:1

We can rewrite it as fractions to get,

\frac{R}{r} = \frac{3}{1}

We make R the subject to get,

R = 3r

The area of the bigger circle can be found using the formula,

Area=\pi {r}^{2}

This implies that,

Area=\pi ({3r})^{2}

Area=9\pi {r}^{2}

But it was given in the question that, the area of the bigger circle is 27π.

27\pi=9\pi {r}^{2}

We divide through by 9π to get,

3 = {r}^{2}

This means that,
r = \sqrt{3}

The area of the smaller circle is therefore

= \pi {( \sqrt{3}) }^{2}

= 3\pi
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Lady_Fox [76]

the price at the end of it will be $16.5.

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