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1 year ago

PLEASE HELP ASAP NUMBER 8 AND 9 SHOW WORK AND I WILL GIVE BRAINLIEST

Mathematics

1 answer:

nasty-shy [4]1 year ago

4 0

Answer:

question 8

Step-by-step explanation:

y = 4

2x + 3y = 22

put y = 4 into equation 2

2x + 3 ( 4) = 22

2x + 12 = 22

2x = 22 - 12

2x = 10

x = 5

therefore x = 5 and y = 4

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Find the value of X(2x + 4) (2x-9)

kotykmax [81]

2x +4)° 2x-9)°= 4x 2 +8x−9=3

Pull out like factors :

2x + 4 = 2 • (x + 2) (4 • (x + 2) • x) - 9

4x • (x + 2) - 9

Factoring 4x2+8x-9

The first term is, 4x2 its coefficient is 4 .

The middle term is, +8x its coefficient is 8 .

The last term, "the constant", is -9

Step-1 : Multiply the coefficient of the first term by the constant 4 • -9 = -36

Step-2 : Find two factors of -36 whose sum equals the coefficient of the middle term, which is 8 .

-36 + 1 = -35

-18 + 2 = -16

-12 + 3 = -9

-9 + 4 = -5

-6 + 6 = 0

-4 + 9 = 5

-3 + 12 = 9

-2 + 18 = 16

-1 + 36 = 35

x=3

6 0

2 years ago

Read 2 more answers

Distance between (-4,4) and (2,4)

9966 [12]

For this case we have that by definition, the distance between two points is given by:

$d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}$

We have to:

$(x_ {1}, y_ {1}) = (- 4,4)\\(x_ {2}, y_ {2}) = (2,4)$

Substituting:

$d = \sqrt {(2 - (- 4)) ^ 2+ (4-4) ^ 2}\\d = \sqrt {(2 + 4) ^ 2 + (4-4) ^ 2}\\d = \sqrt {(6) ^ 2 + (0) ^ 2}$

$d = \sqrt {36}\\d = 6$

ANswer:

$d = 6$

6 0

2 years ago

Read 2 more answers

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

2 years ago

Dana is playing a game where she loses 75 points every time she rolls an even number. She starts with 0 points. Then she rolls a

slavikrds [6]

Answer:

-375

Step-by-step explanation:

-75 * 5

= -375.

3 0

2 years ago

What are the coordinates of the point obtained if the point A=(3,7) is rotated 180 degrees about the origin?

Yuliya22 [10]

Answer:

B. (-3, -7)

Step-by-step explanation:

Anytime you rotate a number 180° about the origin, the numbers in the coordinates become their opposites.

-3 is the opposite of 3 and -7 is the opposite of 7.

Therefore, your new coordinates are (-3, -7)

(x,y) becomes (-x,-y)

8 0

2 years ago