2 years ago

Chould someone help with number 4

Mathematics

1 answer:

Dima020 [189]2 years ago

7 0

-19/12 is your answer if that helps

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The mean of data set A is 42. The mean of data set B is 47. The mean absolute deviation (MAD) of both data sets is 2.5. What is

Ede4ka [16]

Answer:

Step-by-step explanation:

6 0

2 years ago

Walleye is a common game fish. Adult walleye have a length with a mean of 44 cm and a standard deviation of 4 cm, and the distri

Ostrovityanka [42]

Answer:b. 0.22

Step-by-step explanation:

Since the lengths of adult walleye fishes are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = lengths of walleye fishes.

µ = mean length

σ = standard deviation

From the information given,

µ = 44 cm

σ = 4 cm

We want to find the probability or fraction of fishes that are greater than 41 cm in length. It is expressed as

P(x > 41) = 1 - P(x ≤ 41)

For x = 41,

z = (41 - 44)/4 = - 0.75

Looking at the normal distribution table, the probability corresponding to the z score is 0.22

4 0

2 years ago

8x + 6 - 2x = 34 x= ?

e-lub [12.9K]

8x + 6 - 2x = 34x

Simplify 8x +6 - 2x to 6x + 6:
6x + 6 = 34x

Subtract 6x from both sides:
6 = 34x- 6x

Simplify 34x - 6x to 28x:
6 = 28x

Divide both sides by 28:
$\frac{6}{28}$ = x

Simplify $\frac{6}{28}$ to $\frac{3}{14}$ :
$\frac{3}{14}$ = x

Now switch sides and the answer is:

x = $\frac{3}{14}$

:) <3

5 0

2 years ago

Read 2 more answers

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Studentka2010 [4]

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