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guapka [62]
3 years ago
5

Let f(x) = 3x2 + x − 3 and g(x) = x2 − 5x + 1. Find f(x) − g(x)

Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0

Answer:

Step-by-step explanation:

3x^{2}+x-3= x^{2} - 5x

combine like terms

3x^{2} +x^{2}= 4x^{2}

x -5x = -4x

then combine 4x^{2} and -4x

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he width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of the
Ivanshal [37]

The original area of the rectangle is 35ft^{2}

<u>Explanation:</u>

width = x

length = x + 2

area of the rectangle = x (x+2)

length = x + 2 + 5 = x+7

60 = (x+7) (x)\\60=x^{2} + 7x\\x^{2}  + 7x - 60 =0\\

Solving this equation, we get

x =5ft

So, original  width = 5ft

original length = 5+2ft = 7ft

Thus, original area of the rectangle = 5 X 7ft = 35ft^{2}

Therefore, the original area of the rectangle is 35ft^{2}

3 0
4 years ago
What numbers are less than 2.9 and -4.2?
kolbaska11 [484]
The answer is -4.3!!!!!!!
5 0
3 years ago
The function f(x) = x3 – 8x2 + x + 42 has zeros located at 7, –2, 3. Verify the zeros of f(x) and explain how you verified them.
xeze [42]

Answer:

  • zeros are {-2, 3, 7} as verified by graphing
  • end behavior: f(x) tends toward infinity with the same sign as x

Step-by-step explanation:

A graphing calculator makes finding or verifying the zeros of a polynomial function as simple as typing the function into the input box.

<h3>Zeros</h3>

The attachment shows the function zeros to be x ∈ {-2, 3, 7}, as required.

<h3>End behavior</h3>

The leading coefficient of this odd-degree polynomial is positive, so the value of f(x) tends toward infinity of the same sign as x when the magnitude of x tends toward infinity.

  • x → -∞; f(x) → -∞
  • x → ∞; f(x) → ∞

__

<em>Additional comment</em>

The function is entered in the graphing calculator input box in "Horner form," which is also a convenient form for hand-evaluation of the function.

We know the x^2 coefficient is the opposite of the sum of the zeros:

  -(7 +(-2) +3) = -8 . . . . x^2 coefficient

And we know the constant is the opposite of the product of the zeros:

  -(7)(-2)(3) = 42 . . . . . constant

These checks lend further confidence that the zeros are those given.

(The constant is the opposite of the product of zeros only for odd-degree polynomials. For even-degree polynomials. the constant is the product of zeros.)

3 0
2 years ago
How many solutions exist for the given equation?
zmey [24]
<h3> Answer </h3>

x = 2

<h3>Step by step</h3>

1/2(x + 12) = 4x - 1

1/2x + 12/2 = 4x - 1

1/2x + 6 = 4x - 1

1/2x - 4x = -1 - 6

1/2x - 8/2x = -7

-7/2x = -7

x = -14/-7

x = 2

8 0
3 years ago
Kindly solve this question 6 too !!
Shkiper50 [21]

Answer:

x=1

Step-by-step explanation:

~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1

7 0
2 years ago
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