Answer:
np = 81 , nQ = 99
Step-by-step explanation:
Given:
X - B ( n = 180 , P = 0.45 )
Find:
Sampling distribution has an approximate normal distribution
Computation:
nP & nQ ≥ 5
np = n × p
np = 180 × 0.45
np = 81
nQ = n × (1-p)
nQ = 180 × ( 1 - 0.45 )
nQ = 99
Answer:
Step-by-step explanation:
Weekly wages at a certain factory are
normally distributed. The formula for normal distribution is expressed as
z= (x - u)/s
Where
u = mean
s = standard deviation
x = weekly wages
From the given information,
u = 400
s = 50
The probability that a worker
selected at random makes between
$350 and $400 is expressed as
P(350 lesser than or equal to x lesser than or equal to 400)
For x = 350
z = (350 - 400)/50 = -50/50 = -1
z = -1
From the normal distribution table, the corresponding z score is 0.1587
For x = 400
z = (400 - 400)/50 = 0/50 = 0
z = 0
From the normal distribution table, the corresponding z score is 0.5
P(350 lesser than or equal to x lesser than or equal to 400)
= 0.5 - 0.1587 = 0.3413
Answer: C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)
Step-by-step explanation:
The data set is:
(9, 22)
(10,32)
(11, 41)
(12, 30).
In the usual notation, the number at the left is the input (belons to the domain) and the number in the right is the output (belongs to the range).
Then the domain would be:
{9, 10, 11, 12}
and the range:
{22, 32, 41, 30}
The correct option is C
Answer: a=1 b=3
Step-by-step explanation: the x for each of the points are 1 and 3
Answer:
the students that brought a lunch box is 28
Step-by-step explanation:
The computation of the students that brought a lunch box is shown below:
= Entire school students × students that carry a lunch box ÷ entering students
= 84 students × 8 ÷ 24 students
= 28 students
Hence, the students that brought a lunch box is 28
