The graph shows the relationship between the weight of an object on the moon and its weight on Earth.

Mathematics

2 answers:

OLEGan [10]3 years ago

4 0

Answer:

It would have to be B: 6

Step-by-step explanation:

I would say this because I just did a quiz about it. Sorry for no explanation.

shtirl [24]3 years ago

4 0

Answer:

The answer is d

Step-by-step explanation:

You might be interested in

Let x ∼ bin(9, 0.4). find

Kobotan [32]

A.
$\mathbb P(X>6)=\mathbb P(X=7)+\mathbb P(X=8)+\mathbb P(X=9)$
$=\dbinom97(0.4)^7(1-0.4)^{9-7}+\dbinom98(0.4)^8(1-0.4)^{9-8}+\dbinom99(0.4)^9(1-0.4)^{9-9}$
$\approx0.025$

b.
$\mathbb P(X\ge2)=1-\mathbb P(X$
$=1-\dbinom90(0.4)^0(1-0.4)^{9-0}-\dbinom91(0.4)^1(1-0.4)^{9-1}$
$\approx0.929$

c.
$\mathbb P(2\le X$
$=\dbinom92(0.4)^2(1-0.4)^{9-2}+\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}$
$\approx0.663$

d.
$\mathbb P(2$
$=\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}+\dbinom95(0.4)^5(1-0.4)^{9-5}$
$\approx0.669$

e.
$\mathbb P(X=0)=\dbinom90(0.4)^0(1-0.4)^{9-0}\approx0.01$

f.
$\mathbb P(X=7)=\dbinom97(0.4)^7(1-0.4)^{9-7}\approx0.021$

g, h.
For $X\sim\mathcal B(n,p)$ , recall that $\mathbb 
E[X]=\mu_X=np$ and $\mathbb V[X]={\sigma_X}^2=np(1-p)$ . So

$\mu_X=9(0.4)=3.6$
${\sigma_X}^2=9(0.4)(0.6)=2.16$

6 0

3 years ago

Hey there can you please help me posted picture of question

mash [69]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 12
a = coefficient of squared term = 4
c = constant term = 9

Using the values, we get:

$x= \frac{-12+- \sqrt{144-4(4)(9)} }{2(4)} \\ \\ 
x= \frac{-12+-0}{8} \\ \\ 
x= \frac{-3}{2}$

So, the correct answer to this question is option B

5 0

3 years ago

The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016

hodyreva [135]

Answer:

Required Probability = 0.97062

Step-by-step explanation:

We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.

Let X = weight of the newborn baby, so X ~ N( $\mu=4016 , \sigma^{2} = 532^{2}$ )