Answer:
I won't stop the line for a half hour break.
Step-by-step explanation:
<u>Proportions</u>
One quantity A is said to be proportional to other B if A can always be obtained by multiplying or dividing B by any constant number. Numbers {4,8,12} are proportional to {2,4,6} because they can be computed as twice their value
.
There is a situation described in the problem where we need to know if there will be enough time to produce the 900 toasters (the goal for the day) when the assembly line is stopped by half an hour.
Actual time: 2:00 pm
Final time: 5:00 pm
Rate of production: 2 toasters/minute
Actual production: 560 toasters
Updated goal: 900-560 = 340 toasters
Those 340 toasters must be produced in the remaining 3 hours (180 minutes) of work. If the assembly line stops for half an hour (30 minutes), there will be only 150 minutes to finish the goal production. At a rate of 2 toasters/minute, there will be 2*150 = 300 toasters produced. But we need to produce 340 more toasters, so that break cannot be granted or we'll be 40 toasters under goal.
It the line keeps producing for 180 minutes, it would produce 2*180 = 360 toasters, 20 more than the goal.
Note: The maximum break time that can be granted is 20/2 = 10 minutes
Answer:
it's not even hard
Step-by-step explanation:
......
You start with: (assuming x equals the cost to enter and y the cost of going on the rollercoasters.)
x+5y=35
x+11y=59. Multiply the top equation by -1, and subtract the equations, giving you -6y=-24, divide by -6 into both sides of the equation, to get y=4. Now replace y in one of the original equations (I recommend x+5y=35) and solve for x, giving you x=15
The cost for entering is 15 dollars, while each coaster is 4 dollars more. You could simplify this by changing y into x and making it slope-intercept form, to track your cost. y=4x+15, so it has a slope of 4, and a y-intercept of 15. This answer should give you a good grade on a test.
Answer:
A
Step-by-step explanation:
Given
y =
← cancel x on numerator/ denominator
= 
Cancelling the factor x, leaves a hole in the graph at x = 0