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2 years ago

Ryan bought 43 pounds ofapples for $0.75 per pound. Howmuch did he pay for the apples?

Mathematics

2 answers:

Rasek [7]2 years ago

8 0

Answer:32.25$

Step-by-step explanation:

0.75x43=32.25

kirill115 [55]2 years ago

5 0

Answer:32.25

Step-by-step explanation:

For every pound there is $.75, so you just multiply them

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Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

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2 years ago

Sasha and Mona practiced swimming every day. They increased the number of minutes of swimming every week as described below:

vagabundo [1.1K]

D. Sasha's method is exponential because it increases by a fixed factor, and Mona's method is linear because it increases by a fixed number.

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Rainbow [258]

Answer:

$A\cap B={2,4}$

Step-by-step explanation:

Intersection represents the elements present in both sets.

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2 years ago

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The table shows the last holiday destination of 60 people

Licemer1 [7]

Answer:

Use your protractor to draw the lines

Step-by-step explanation:

You worked out the angles, so using the centre point as the middle and the line underneath France as your starter line, do 108° sector for Spain, then a 90° for Greece and a 12° for Others

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1 year ago

there is a direct path from gayle's house to the store. due to construction, the direct route is closed and gayle must travel 6

NikAS [45]

Answer:

c2=10

Step-by-step explanation:

8^2+6^2=c2

64+36=120

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Ryan bought 43 pounds ofapples for $0.75 per pound. Howmuch did he pay for the apples?​

Ryan bought 43 pounds ofapples for $0.75 per pound. Howmuch did he pay for the apples?