Answer:
a)
if 1 quarter = $ 0.25
1 dime = $ 0.10
1 penny = $ 0.01
so to make the total of $1.08 and its is also required to calculate the number of each coins present without being able to make change for a dollar
therefore we say;
1 Quarter + 8 dimes + 3 penny
: ( 1 × 0.25 ) + ( 8 × 0.10 ) + ( 3 × 0.01 )
: 0.25 + 0.80 + 0.03 = $ 1.08
b)
Now if you have a 4 Quarters, you have change for $1.
If you have 5 dimes, you have change for 2 Quarters.
If you have nickel; one of those can combine with 2 dimes to have a change for a Quarter.
If you have 5 pennies, you have enough change for 1 nickel
Therefore
(4-1)×0.25 + (5-1)×0.1 + (0×0.05) + (5-1)×0.01 = x
(3 × 0.25) + ( 4 × 0.1) + 0 + ( 4 × 0.01) = x
x = 0.75 + 0.4 + 0.04
x = $ 1.19
PROVED
Use the sum-product pattern
2
−
−
1
2
x
2
−
x
−
12
x2−x−12
2
+
3
−
4
−
1
2
x
2
+
3
x
−
4
x
−
12
x2+3x−4x−12
2
Common factor from the two pairs
2
+
3
−
4
−
1
2
x
2
+
3
x
−
4
x
−
12
x2+3x−4x−12
(
+
3
)
−
4
(
+
3
)
x
(
x
+
3
)
−
4
(
x
+
3
)
x(x+3)−4(x+3)
3
Rewrite in factored form
(
+
3
)
−
4(+3)x
(x+3)−4(x+3)
x(x+3)−4(x+3)
(−4)(+3)
(x−4)(x+3)
(x−4)(x+3)
Answer:
- 150π ft²
- 10π ft.
Step-by-step explanation:
Area of the sector :
Finding the area given r = 30 ft. and θ = 60° :
⇒ Area = π × (30)² × 60/360
⇒ Area = π × 900/6
⇒ Area = 150π ft²
===========================================================
Length of the arc :
Finding the arc length given r = 30 ft. and θ = 60° :
⇒ Arc Length = 2 × π × 30 × 60/360
⇒ Arc Length = 60/6 × π
⇒ Arc Length = 10π ft.
