Answer:
the point is (3, 3) . . . . . . y = 3
Step-by-step explanation:
Write the point-slope equation of the line through the point you know. Then evaluate that equation for x=3 to see what the value of y is.
Point-slope form:
y = m(x -h) +k . . . . slope m through point (h, k)
y = -1/2(x -9) +0 . . . . line with slope -1/2 through point (9, 0)
For x=3, the value of y is ...
y = -1/2(3 -9) + 0 = -1/2(-6) = 3
The value of y is 3.
NO is 2 times LM
2(x+1) = 4x
2x + 2 = 4x
2 = 2x
1 = x
Plug that in for 4x
4(1)
4
You can reword the two equations as:
-5x-y=15 (Divide original value by 3)
-2x+6y=6
Then use elimination to find x:
-30x-6y=90 (Multiply by 6 to get y values to be same to cancel out)
-2x+6y=6
You're left with:
-32x=96. Which can then be solved to find x which is -3.
Then plug back in
-2x+6y=6
Now to: -2(-3)+6y=6.
Which reduces to 6+6y=6. So y=0.
To graph them, just reword the equations (yes once again) so that y is in front.
y=-5x-15 and y=(1/3)x+1
Add 5 to both sides of the equation.
x=-14+5
Add -14 and 5.
x=-9
You plug 11 in where x is.
r(11) = (11 + 1)(11 - 3)
= (12)(8)
= 96
