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ruslelena [56]
3 years ago
11

The correct answer is...?

Mathematics
1 answer:
Elanso [62]3 years ago
8 0

<em>Answer:</em>

<em>The answer to both problems is </em><em><u>GRAPH</u></em>

<em>I hope this helps:)</em>

You might be interested in
32% of 1600 = 512
yaroslaw [1]

Answer:

  • 64%: 1024
  • 96%: 1536
  • 132%: 2112
  • 232%: 3712

Step-by-step explanation:

<u>64% of 1600</u>

  64% of 1600 = 2 × (32% of 1600) = 2×512

  64% of 1600 = 1024

<u>96% of 1600</u>

  96% of 1600 = 3 × (32% of 1600) = 3×512

  96% of 1600 = 1536

<u>132% of 1600</u>

  132% of 1600 = (100% of 1600) + (32% of 1600) = 1600 + 512

  132% of 1600 = 2112

<u>232% of 1600</u>

  232% of 1600 = (100% of 1600) + (132% of 1600) = 1600 +2112

  232% of 1600 = 3712

3 0
3 years ago
Read 2 more answers
Hello can someone help me with this?
zalisa [80]

Answer:

  1. 1
  2. 1/2
  3. 1/5
  4. 2
  5. 10
  6. 0
  7. -1
  8. -1/2
  9. -1/5
  10. -2
  11. -10

4 0
3 years ago
Which of the following numbers is NOT a solution<br> of the inequality 3x – 5&gt;_4x – 3 ?
Arte-miy333 [17]

Answer:

A)-1

Step-by-step explanation:

3x-5≥4x-3

3x-4x≥-3+5

-x≥2

x≤-2

(-infinity,-2]

-1 x

-2,-3,-5 ✓

8 0
3 years ago
in the following diagrams ABD=y,DBC=x,EFH=y, EFG=x and PQS=SQR=x.write the following in terms of x and y ABC
Leokris [45]

Angles are the space between intersecting lines, and they are measured in degrees or radians

The measure of angle ABC is y + x

<h3>How to determine angle ABC</h3>

The given parameters are:

ABD=y,

DBC=x,

EFH=y,

EFG=x

PQS = SQR = x

To determine the measure of angle ABC, we make use of angle ABD and angle DBC

Note that angle ABD and angle DBC have common vertices at points B and D

So, we have:

ABC = ABD + DBC

Substitute known values

ABC = y + x

Hence, the measure of angle ABC is y + x

Read more about angle measures at:

brainly.com/question/17972372

3 0
3 years ago
Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
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