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3 years ago

Need answers please

Mathematics

2 answers:

vivado [14]3 years ago

7 0

Divide $125 into $20

Delvig [45]3 years ago

6 0

The answer is 0.16 did I help you or not

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Questions:

MrRa [10]

Answer:

i dont uderstand sorry

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Find an equation of the sphere with center (4, −12, 8) and radius 10.

Lorico [155]

Answer:

Step-by-step explanation:

To find an equation of the sphere with center (4, −12, 8) and radius 10

$(x-4)^2+(y+12)^2+(z-8)^2 = 100$

intersection with xy-plane

Put z=0

$(x-4)^2+(y+12)^2+(0-8)^2 = 100$

$(x-4)^2+(y+12)^2 = 36$

(A circle with centre at (4,-12) and radius 6)

intersection with xz-plane

Put y =0

$(x-4)^2+(0+12)^2+(z-8)^2 = 100$

$(x-4)^2+(z-8)^2 = -44$

Sum of squares cannot be positive, so DNE

intersection with yz-plane

Put x=0

$(0-4)^2+(y+12)^2+(z-8)^2 = 100$

$(y+12)^2+(z-8)^2 = 84$

A circle in YZ plane with centre at y =-12 and z =8 and radius square root of 84

5 0

3 years ago

**15 Points!! What is 2 1/2 x 1 1/2, 5.4 x 2 3/4, and 3.1 x 2/7?

Amiraneli [1.4K]

3.75
14.85
0.89
Those are the answers

6 0

4 years ago

Type the correct answer in each box. Use numerals instead of words. What are the x-intercept and vertex of this quadratic functi

ohaa [14]

Answer:

The x-intercept is (3,0).

The vertex of the function is (3,0).

Step-by-step explanation:

Given : Function $g(x)=-5(x-3)^2$

To find : What are the x-intercept and vertex of this quadratic function?

Solution :

Function $g(x)=-5(x-3)^2$

The x-intercept is when g(x)=0.

i.e. $-5(x-3)^2=0$

Divide by -5 both side,

$(x-3)^2=0$

Taking root both side,

$x-3=0$

Add 3 both side,

$x=3$

The x-intercept is (3,0).

The general vertex form of the quadratic function is $y=a(x-h)^2+k$

where, (h,k) is the vertex

Compare the given function $g(x)=-5(x-3)^2$

a=-5 , h=3 and k=0

The vertex of the function is (3,0).

6 0

3 years ago

Find the midpoint of the segment with the following endpoints.<br> (6,4) and (9,1)

olasank [31]

Answer:

$=\left(\frac{15}{2},\:\frac{5}{2}\right)$

Step-by-step explanation:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(6,\:4\right),\:\left(x_2,\:y_2\right)=\left(9,\:1\right)\\\\=\left(\frac{9+6}{2},\:\frac{1+4}{2}\right)\\\\=(\frac{15}{2} , \frac{5}{2} )\\\\$

7 0

3 years ago