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lord [1]
2 years ago
11

The area of the Indian Ocean is what percent of the area of the Pacific ocean? ROund to the nearest whole?show your work

Mathematics
1 answer:
Bumek [7]2 years ago
4 0
Pacific
64/100
Indian
25/100
64/100-25/100=39/100
39/100=39%
I'm not sure but I think 39% is the answer. Better to google it ;)
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Can you find x I don’t know how.
kodGreya [7K]

Answer:

7

Step-by-step explanation:

(x+3)/(x+8) = 2/3

3x + 9 = 2x + 16

x = 7

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In which area of the brain does mathematical processing occur?
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The perimeter of a triangle is 199 inches. If one side of the triangle is six more than the shorter side, and the longer side is
Keith_Richards [23]
Shortest side (a) = 58
middle side (b) = 64
longest side (c) = 77

the 3 sides a + b + c = 199
b = a + 6
c = a + 19

substitute your new values for b & c into your original formula, so:
a + (a+6) + (a+19) = 199
3a + 25 = 199
3a = 174
a = 58

then substitute 58 into your b & c formulas to figure out the rest
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3 years ago
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Jobisdone [24]

Answer:

54

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Ans

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3 years ago
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Levart [38]

Area of the figure = 806.5 in²

Solution:

Length of the rectangle = 16 in

Breadth of the rectangle = 9 in

Area of the rectangle = length × breadth

                                    = 16 × 9

Area of the rectangle = 144 in²

Base of the triangle = 31 in

Height of the triangle = 20 in

Area of the triangle = \frac{1}{2}bh

                                 $=\frac{1}{2}\times 31\times 20

Area of the triangle = 310 in²

Parallel sides of the trapezium = 16 in and 31 in

Height of the trapezium = 35 – 20 = 15 in

Area of the trapezium = \frac{1}{2}\times \text{Sum of the parallel sides}\times \text{Height}

                                     $=\frac{1}{2}\times {(16+31)}\times{15}

                                     $=\frac{1}{2}\times {47}\times{15}

Area of the trapezium = 352.5 in²

Area of the figure = Area of rectangle + Area of triangle + Area of trapezium

                              = 144 in² + 310 in² + 352.5 in²

Area of the figure = 806.5 in²

8 0
3 years ago
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